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What else can I help you with?
To construct a perpendicular bisector to a given line segment one must construct two?
Equilateral triangles
Which types of triangles must always have at least one angle bisector that is also a perpendicular bisector?
iscoceles triangle! =)
What Line t is the perpendicular bisector of FG. If line t intersects FG at point H statements must be true Check all that apply.?
The answer letters always rearrange so here are the answers point H is the midpoint of FG line t intersects FG at a right angle Line T is perpendicular to FG
In the diagram below rs is the perpendicular bisector of PQ. statements must be true Check all that apply.ing?
T is the midpoint of PQangle PTR = 90 degreesRS _l_ PQPT = QT
Does a diameter that is perpendicular to a chord bisect the chord?
Yes, any diameter which is perpendicular to a chord bisects said chord. This can be proved most easily with a picture, but is proved using a congruent triangle proof. Both triangles include the points at the center of the circle and the intersection of the diameter and chord. The other points should be the endpoints of the chord. They are congruent by hypotenuse leg; it was given that they are right triangle by the "perpendicular", the "leg" is the segment between the center of the circle and the intersection, and it is equal in both triangles because it is the same segment in both triangles. The hypotenuses are equal because both are radii of the circle. Because the triangles are congruent, their sides must be so the two halves of the chord are congruent, and therefore the chord is bisected by the diameter.
When constructing a perpendicular bisector why must the compass opening be greater than the length of the segment?
So that the arc is mid-way in perpendicular to the line segment
To construct a perpendicular bisector to a given line segment one must construct two?
Equilateral triangles
Must a bisector of a segment always be a perpendicular line?
Not always because the diagonals of a rectangle bisect each other but they are not perpendicular to each other.
What must you do to construct the midpoint of a segment?
With a straight-edge and a compass:Swing arcs from each end of the segment with the compass (without changing the settings)Connect the intersections of these arcs.The resultant is a perpendicular bisector of the segment.
Which types of triangles must always have at least one angle bisector that is also a perpendicular bisector?
iscoceles triangle! =)
What triangle must always have at least one angle bisector that is also a perpendicular bisector?
any isosceles triangle
How is line m is the perpendicular bisector of XY. If line m intersects XY at point Z statements must be true?
The perpendicular bisector of the line XY will meet it at its midpoint at right angles.
To construct a perpendicular bisector to a given line segment one must construct two what?
Can't be sure what you're asking, but it would be two circles with equal radii longer that half the length of the segment, using the endpoints as the origins of the two circles.
Line BE is the bisector of segment AC. If AB 7 then AC .?
If line BE is the bisector of segment AC, it means that BE divides AC into two equal segments. Therefore, if AB is 7, then AC must be twice that length, making AC equal to 14.
Can a segment bisect a line?
No. Since a line is infinite, it has no mid-point. A bisector must go through a midpoint so nothing can bisect a line (not even a segment).
How do you construct a perpendicular bisector of each side of a parallelogram?
With a compass and a straight edge and the lines must bisect each other at 90 degrees
What Line t is the perpendicular bisector of FG. If line t intersects FG at point H statements must be true Check all that apply.?
The answer letters always rearrange so here are the answers point H is the midpoint of FG line t intersects FG at a right angle Line T is perpendicular to FG
