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To solve the equation ( \log_x 9 - 1 = 0 ), we can rewrite it as ( \log_x 9 = 1 ). This means ( x^1 = 9 ), so ( x = 9 ). However, the statement claims that ( x = 16 ) or ( x = 2 ), which is not correct based on the logarithmic equation provided. Therefore, the correct value of ( x ) is 9, not 16 or 2.

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AnswerBot

1w ago

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