To solve the equation ( \log_x 9 - 1 = 0 ), we can rewrite it as ( \log_x 9 = 1 ). This means ( x^1 = 9 ), so ( x = 9 ). However, the statement claims that ( x = 16 ) or ( x = 2 ), which is not correct based on the logarithmic equation provided. Therefore, the correct value of ( x ) is 9, not 16 or 2.
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To find ( \frac{1}{18} ) of 162, divide 162 by 18. Doing the calculation gives ( 162 \div 18 = 9 ). Therefore, ( \frac{1}{18} ) of 162 is 9.
X/9 = 18 multiply through by 9 X = 162 check 162/9 = 18 18 = 18 checks
Two numbers that multiply to negative 162 can be -9 and 18, since -9 × 18 = -162. Alternatively, another pair could be -1 and 162, as -1 × 162 also equals -162. There are multiple pairs of numbers that can achieve this product.
The factors of 162 are 1, 2, 3, 6, 9, 18, 27, 54, 81, and 162.
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These factor pairs, when multiplied together, equal 162: (1, 162) (2, 81) (3, 54) (6, 27) (9, 18)
To find ( \frac{1}{18} ) of 162, divide 162 by 18. Doing the calculation gives ( 162 \div 18 = 9 ). Therefore, ( \frac{1}{18} ) of 162 is 9.
X/9 = 18 multiply through by 9 X = 162 check 162/9 = 18 18 = 18 checks
9/162 = 3/54 = 1/18
The factors of 27 are 1, 3, 9, and 27 The factors of 162 are 1, 2, 3, 6, 9, 18, 27, 54, 81, and 162
Two numbers that multiply to negative 162 can be -9 and 18, since -9 × 18 = -162. Alternatively, another pair could be -1 and 162, as -1 × 162 also equals -162. There are multiple pairs of numbers that can achieve this product.
The factors of 162 are 1, 2, 3, 6, 9, 18, 27, 54, 81, and 162.
Expressed as a proper fraction in its simplest form, 90/162 is equal to 5/9 or five ninths.
18 / (1/9) = 18 * (9/1) = 162
81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9. So 199 is the only one not divisible by 9.
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