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What does n over 12 equals 20 over 30 Please help?
If n is the variable then it's making the two sides equal to one another. So the question is what is n, if n/12 = 20/30 ? First of all 20/30 is 2/3 when that fraction is reduced. Once you have n/12 = 2/3 ... isolate the n, in the equation so... n = (2/3) x 12 .... therefore n = 8. We can prove this by substituting 8 to n .... 8/12 is equivalent to 2/3 whereas 20/30 is equivalent to 2/3. Thus 2/3 = 2/3.
What is n in this equation 2 plus n-3 equals 6?
2+n-3 = 6 n = 6+3-2 n= 7
If n plus 2 times 3 equals 21 what is n?
n + (2 x 3) = 21 Therefore, n = 21 - (2 x 3) n = 15
What is 3n plus 3 equals n plus 7?
3n+3=n+7 3n+3-n=n+7-n (subtract n from both sides) 2n+3=7 2n+3-3=7-3 (subtract 3 from both sides ) 2n=4 2n/2=4/2 (divided by 2 on both the sides) n=2 Answer: n=2
What is an example of using recursive functions?
Let's take the example of finding the factorial of a number (of a positive integer). The factorial of N is N * (N-1) * (N-2) * (N-3) ... * 3 * 2 *1 It is the product of all integers between that number (including that number) and 1. For example, factorial 2 = 2*1 = 2 factorial 3 = 3*2*1 = 6 factorial 4 = 4*3*2*1= 24 Now you define a recursive function Fac (N) as Fac (N) = Fac (N-1) * N, with Fac(1) predefined as 1. Thus, Fac(N-1) = Fac(N-2) * (N-1) and Fac(N-2) = Fac(N-3) * (N-2) and thus recursion takes over until such time fac(1) needs to be evaluated. We know the value of Fac(1) which is set as 1. Thus we can evaluate Factorial(N) using recursion.
What is the answer to 2 over 16 equals n over 3?
n = 3/8
What is n over 2 plus 5 equal 3?
n ___ = 3 2+5 n = 3(2+5) n = 3(7) n = 21
What does n over 12 equals 20 over 30 Please help?
If n is the variable then it's making the two sides equal to one another. So the question is what is n, if n/12 = 20/30 ? First of all 20/30 is 2/3 when that fraction is reduced. Once you have n/12 = 2/3 ... isolate the n, in the equation so... n = (2/3) x 12 .... therefore n = 8. We can prove this by substituting 8 to n .... 8/12 is equivalent to 2/3 whereas 20/30 is equivalent to 2/3. Thus 2/3 = 2/3.
What are the next 3 terms in the sequence 2 over 1 and 3 over 2 and 4 over 3 and 5 over 4 showing a rule for the nth term?
If you mean 2/1 3/2 4/3 5/4 then the next 3 terms are 6/5 7/6 8/7 and the nth term is (n+1)/n
Is 1 over 5 greater than 2 over 3?
N. O. No.
When you divide the number by 5 there are 3 left over and when you divide the number by 8 there are 2 left over?
The answer is any member of the sequence 40n - 22 for n = 1, 2, 3, ...The answer is any member of the sequence 40n - 22 for n = 1, 2, 3, ...The answer is any member of the sequence 40n - 22 for n = 1, 2, 3, ...The answer is any member of the sequence 40n - 22 for n = 1, 2, 3, ...
Multiple by 8 without using multiplication or addition Now do the same with 7?
Let n = the number multiplying by For 8 (n-n)-n-n-n-n-n-n-n-n / -1 Example: let n = 3 (3-3)-3-3-3-3-3-3-3 = -24 / -1 = 24 Proof 8*3 = 24 For 7 (n-n)-n-n-n-n-n-n-n / -1 Example: let n = 2 (2-2)-2-2-2-2-2-2-2 = -14 / -1 = 14 Proof 7*2 = 14 Alternatively: Let n and m represent the numbers to multiply together Formula is m / ( 1 / n) i.e. to multiply n=3 by m=8 x = 8 / ( 1 / 3) = 24
What is the answer to 9 over 6 equals 21 over n?
9/6 = 21/n3/2 = 21/n Since 3 x 7 = 21, then n must be 14 (2 x 7) and we have:3/2 = 21/14 or 9/6 = 21/14.
What is n in this equation 2 plus n-3 equals 6?
2+n-3 = 6 n = 6+3-2 n= 7
What is 5 plus 3 plus 2 equals 5 plus 3 plus n?
That would be 18+n. 5+3+2 = 5+3+n 10 = 8 + n 10-8 = n 2 = n and if you substitute 2 for n then you see that 5+3+2 = 5+3+2
What is the answer to 4 divided by 8 over n to the power of 3?
(4/8)/(n^3)...4/8 reduces to 1/2 so the problem reduces to (1/2)/(n^3)...Which written in simple terms is 1/n^3. Actually I made a typo the answer is 1/(2n^3) Sorry about that.
How do you complete this number pattern in 2 possible ways 1 2 4?
Some, out of infinitely many possible ways, are: 1, 2, 4, 10 : U(n) = (n^3 - 5*n^2 + 10*n - 4)/2 for n = 1, 2, 3, 4 1, 2, 4, 9 : U(n) = (2*n^3 - 9*n^2 + 19*n - 6)/6 for n = 1, 2, 3, 4 1, 2, 4, 8 : U(n) = (3*n^3 - 3*n^2 + 8*n)/6 for n = 1, 2, 3, 4 1, 2, 4, 8 : U(1) = 1, U(n+1) = 2*U(n) for n = 1, 2, 3, 4 Note that the last two are the same sequence but with entirely different rules.
