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tan θ = √3.

tan-1(√3) = π/3 radians or 4π/3 radians, in degrees it would be 60° or 240°

tan θ = sin θ / cos θ

So, tan (π/3) = sin (π/3) / cos (π/3) = tan (4π/3) = sin (4π/3) / cos (4π/3)

cos (π/3) = 1/2

cos (4π/3) = -1/2

Therefore cos θ = 1/2 or -1/2 when tan θ = √3

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Q: If tan is square root of 3 what is cos?
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