45*
Tan[sqrt(3) radians] = tan(1.7321) = -6.1475
tan(sqrtX) + C
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sqrt(3sin(x)=cos(x)=0 // Square both sides3sin(x) + cos(x) = 0 // subtract cos(x) from both sides3sin(x) = -cos(x) // rearrangesin(x)/cos(x) = -1/3 //sin(x)/cos(x) = tan(x)tan(x) = -1/3x = tan^-1(-1/3) == -18,43484882 // tan^-1(inverse tan)
45*
Negative 1.047197551 etc, etc.
square root of 3
tan(60°) = sqrt(3)
Because: tan(60) = square root of 3
Tan[sqrt(3) radians] = tan(1.7321) = -6.1475
The answer, assuming that 120 is degrees and not radian is -square root of 3.
If tan theta equals 2, then the sides of the triangle could be -2, -1, and square root of 5 (I used the Pythagorean Theorem to get this). From this, sec theta is negative square root of 5. It is negative because theta is in the third quadrant, where cosine, secant, sine, and cosecant are all negative.
tan(sqrtX) + C
tan(pi/3) = tan (60 degrees) = 1.732 which is square root of 3
3.6667
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