It will be the same.
The volume is doubled.
increase
you can easely calculate it: the original measurements: 6(bottom)*6(height)*½=18 double the base half the height: 12*3*½=18 so it remains the same
Area of a rectangle is Base(B) times Height(H).Area of smaller rectangle is BH.Area of larger rectangle is 2BH.Area of larger rectangle is twice as large as the smaller rectangle.
The volume of a cylinder is calculated using the formula ( V = \pi r^2 h ), where ( r ) is the radius and ( h ) is the height. If the height is doubled and the radius is halved, the new volume becomes ( V' = \pi \left(\frac{r}{2}\right)^2 (2h) = \pi \left(\frac{r^2}{4}\right)(2h) = \frac{\pi r^2 h}{2} ), which is half the original volume. Thus, the volume of the cylinder decreases to 50% of its original size.
The volume is doubled.
The volume of a circular cylinder varies directly with the height of the cylinder and with the square of the cylinder's radius If the height is halved and the radius is doubled then the volume will be increased.
The exact same as the original triangle.
increase
you can easely calculate it: the original measurements: 6(bottom)*6(height)*½=18 double the base half the height: 12*3*½=18 so it remains the same
Area of a rectangle is Base(B) times Height(H).Area of smaller rectangle is BH.Area of larger rectangle is 2BH.Area of larger rectangle is twice as large as the smaller rectangle.
The volume of a cylinder is calculated using the formula ( V = \pi r^2 h ), where ( r ) is the radius and ( h ) is the height. If the height is doubled and the radius is halved, the new volume becomes ( V' = \pi \left(\frac{r}{2}\right)^2 (2h) = \pi \left(\frac{r^2}{4}\right)(2h) = \frac{\pi r^2 h}{2} ), which is half the original volume. Thus, the volume of the cylinder decreases to 50% of its original size.
The volume will be doubled.
The volume of a pyramid is given by the formula ( V = \frac{1}{3} \times \text{Base Area} \times \text{Height} ). If the height is halved, the new volume becomes ( V' = \frac{1}{3} \times \text{Base Area} \times \frac{\text{Height}}{2} ), which simplifies to ( V' = \frac{1}{2} \times V ). Therefore, when the height of a pyramid is halved, the volume is also halved.
Rectangle area = (rectangle width) x (rectangle height)
The area is multiplied by 4, not doubled.
As area_of_parallelogram = base x height if they are both doubled then: new_area = (2 x base) x (2 x height) = 4 x (base x height) = 4 x area_of_parallelogram Thus, if the base and height of a parallelogram are [both] doubled, the area is quadrupled.