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What does c equal if c squared plus c squared plus 8 equals 8c?
2. c2 + c2 + 8 = 8c 2c2 - 8c + 8 = 0 c2 - 4c + 4 = 0 (c - 2)(c - 2) = 0 (c - 2)2 = 0 c - 2 = 0 c = 2
Square root of 8-c equals c-8?
16
The hypotenuse of a right triangle with legs of lengths 8 and 15?
Let c be the hypotenuse and use the Pythagorean theorem. 8^2 + 15^2 = c^2 64 + 225 = c^2 289 = c^2 17 = c
Given a equals 4 b equals -2 and c equals 8 evaluate 3abc?
a=-2 4b=-2 --> b=-1/2 c=8 (-2)(-1/2)(8)(3)= 24
How can you Find the length of the hypotenuse of a right triangle with legs of lengths 8 and 15 If necessar?
using the pythagorean thereom. a^2 + b^2 = c^2 in which a and b are your legs and c is your hypotenuse 8^2 + 15^2 = c^2 289=c^2 17 is the hypotenuse
What is the product of c 8 and c-5?
(c + 8)(c - 8)= c^2 - 64
What does c equal if c squared plus c squared plus 8 equals 8c?
2. c2 + c2 + 8 = 8c 2c2 - 8c + 8 = 0 c2 - 4c + 4 = 0 (c - 2)(c - 2) = 0 (c - 2)2 = 0 c - 2 = 0 c = 2
Which equation should be used to find the eccentricity of the earths orbit?
Eccentricity is the measure of how much the conic section diverges into its circle form. One of the formulas for eccentricity is e=c/a this formula can be used to get the eccentricity of the ellipse.
What is the eccentricity of an ellipse in which the distance between the foci is 2 centimeters and the length of the major axis is 5 centimeters?
The eccentricity of that ellipse is 0.4 .
What does 8 is 2 C mean?
8 = 2 cubed
Square root of 8-c equals c-8?
16
The hypotenuse of a right triangle with legs of lengths 8 and 15?
Let c be the hypotenuse and use the Pythagorean theorem. 8^2 + 15^2 = c^2 64 + 225 = c^2 289 = c^2 17 = c
Which planet has an orbital eccentricity most like the orbital eccentricity of the moon?
Mercury has an orbital eccentricity most similar to the moon's orbital eccentricity, which is about 0.2056. Mercury's eccentricity is approximately 0.206.
What 2 planets have the most cicular orbits?
Venus has an eccentricity of 0.00677323 Neptune has an eccentricity of 0.00858587 Triton, a moon of Neptune, orbit is as close to a perfect circle with an eccentricity of 0.000016 The Earth for comparison has an eccentricity of 0.01671022
Given a equals 4 b equals -2 and c equals 8 evaluate 3abc?
a=-2 4b=-2 --> b=-1/2 c=8 (-2)(-1/2)(8)(3)= 24
8=−2/5c?
C=20
Is an ellipse is similar to a circle?
How is a circle similar to an ellipse?The eccentricity of a circle is zero.The eccentricity of an ellipse which is not a circle is greater than 0, but less than 1.The eccentricity of a parabola is 1The eccentricity of a hyperbola is greater than 1Definition of eccentrica person with an unusual or odd personalitybizarre: conspicuously or grossly unconventional or unusual;.A circle is the perfect shape, all point are equidistant from the center. I believe we could agree that the circle has no eccentricity!!The eccentricity of a circle is zero..On the other hand the ellipse has points that 2 centers, a little eccentric. The farther the 2 points are apart the more eccentric the ellipse is.If you take any point on the ellipse, the sum of the distances to the focus points is constant. The eccentricity of an ellipse which is not a circle is greater than 0, but less than 1.If you stretch the ellipse too far it will break open and be a parabola. The eccentricity of a Parabolais 1. The parabola just keeps spreading out in both directions. At least it is still symmetrical. It has bottom (vertex),but the top just keeps spreading out.The eccentricity of a parabola is 1The eccentricity of a hyperbola is greater than 1The points on a hyperbola get close to the x-axis and y-axis, but never touch either axis.The eccentricity of a circle is zero. Think about the equation of each of these shapes Circle x^2 + y^2 = r ^2 How beautiful y^2 = r ^2 - x^2The eccentricity of an ellipse which is not a circle is greater than 0, but less than 1.Ellipse Equation(x^2 ÷ a^2) + (y^2 ÷ b^2) = 1Getting more eccentric with those a^2's an b^2'sParabola EquationY = k * x^2Now poor y is not squared The eccentricity of a parabola is 1Hyperbola Equationx * y = constanty = constant ÷ xNow poor x is in the denominator The eccentricity of a hyperbola is greater than 1
