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Let's do an example.

Draw an isosceles trapezoid. Let say that the biggest base has a length of 10, and the smallest base has a length of 4.

Draw two perpendicular line that pass through the vertices of the smallest base, to the biggest base of the trapezoid.

A rectangle is formed whose lengths of its two opposite sides equal to the length of the smallest base of the trapezoid.

Then, we can say that the base of the right triangle whose hypotenuse is one one of the congruent sides of the trapezoid is 3, (1/2)(10 -4). So that one of the possibilities of its height (which also is the height of the trapezoid) is 4, and the hypotenuse is 5 (by the Pythagorean triple).

Now, in the right triangle whose hypotenuse is one of the congruent sides of the trapezoid, we have:

tan (base angle of the trapezoid) = 4/3, and

the base angle angle of the trapezoid = tan-1 (4/3) ≈ 53⁰.

Since the sum of the two adjacent angles of the trapezoid is 180⁰, the other angle of the trapezoid is 127⁰.

Thus, the base angles of the isosceles trapezoid have a measure of 53⁰, and two other angles have a measure of 127⁰.

So, we need to have more information in order to find the angles of the isosceles trapezoid for the given problem.

Q: If the length of the bases of an isosceles trapezoid are known can you compute the measure of the internal angles?

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Only when it is an isosceles trapezoid otherwise no.

You prove that the two sides (not the bases) are equal in length. Or that the base angles are equal measure.

A quadrilateral may have all 4 angles different if it is not a square, rectangle, rhombus, rhomboid, rectangular trapezoid, isosceles trapezoid, or parallellogram.

For an isosceles triangle with vertex 46 degrees, the sum of the remaining two base angles is 180-46 = 134 degrees. Base angles are equal because it's isosceles, so each angle is half of their sum. 134/2 = 67 degrees. Thus, any isosceles trapezoid formed inside that isosceles triangle by drawing parallel lines to the triangle's base, will have base angle measures of 67 degrees, which are triangle's base angles.

Since the sum of the angles in a triangle is 180Â°, then the two base angles sum to (180Â° - 38Â° = 142Â°). In isosceles, these two angles are equal, so each one is:142Â° / 2 = 71Â°

Related questions

There is no figure to be seen but an isosceles trapezoid will have equal base angles.

There is no figure to be seen but an isosceles trapezoid will have equal base angles.

There is no figure to be seen but an isosceles trapezoid will have equal base angles.

Only when it is an isosceles trapezoid otherwise no.

28.5 units

The isosceles trapezoid will have 2 equal base angles of 50 degrees and 2 other equal angles of 130 degrees.

You prove that the two sides (not the bases) are equal in length. Or that the base angles are equal measure.

A quadrilateral may have all 4 angles different if it is not a square, rectangle, rhombus, rhomboid, rectangular trapezoid, isosceles trapezoid, or parallellogram.

50

The average(mean) of the two bases. (8+12)/2=10

For an isosceles triangle with vertex 46 degrees, the sum of the remaining two base angles is 180-46 = 134 degrees. Base angles are equal because it's isosceles, so each angle is half of their sum. 134/2 = 67 degrees. Thus, any isosceles trapezoid formed inside that isosceles triangle by drawing parallel lines to the triangle's base, will have base angle measures of 67 degrees, which are triangle's base angles.

Since the sum of the angles in a triangle is 180Â°, then the two base angles sum to (180Â° - 38Â° = 142Â°). In isosceles, these two angles are equal, so each one is:142Â° / 2 = 71Â°