Assume the area of the rectangle is 70 squarecentimeters.Convert the length to centimeters : 1 meter = 100 cm : 10 meters = 1000 cmArea of a rectangle = length x width.70 = 1000 x width : width = 70/1000 = 0.07 cmPerimeter of a rectangle = 2 (length + width) = 2(1000 + 0.07) = 2 x 1000.07 = 2000.14 cm = 2000.14/100 = 20.0014 meters.
Area = 150 square yards. A=l x w; Perimeter = 2(w + l): l = 6w; 2(w+6w)=2w + 12 w; 14w = 70; w=70/14=5; 6w = 30; therefore 5 x 30 = 150.
34 feet
(70/10) m
Assuming that you have a rectangle shaped area, 20 yards long by 15 yards wide, and you want to completely enclose the area with the fencing, then you have a problem where you need to find the perimeter of a rectangle. Perimeter = 2 * Length + 2 * Width Perimeter = 2 * (20 yd) + 2 * (15 yd) = 40 yd + 30 yd = 70 yards
24000 sq.cm.
For a start at this question, find out how wide this rectangle must be. area (250) = length (25) x width (???) The area of a rectangle is its length times its width. We should divide the area by the length (25) to get the width. The answer is 10. Then we know that each long side is 25 and each short side is 10. We know that in a rectangle, the long sides are the same length and the short sides are the same width. In order to get the perimeter, we add 25 and 25 and 10 and 10. We get 70. So the perimeter is 70.
(70 + 75) x 2
Perimeter of rectangle: 2*(20+15) = 70m
Assume the area of the rectangle is 70 squarecentimeters.Convert the length to centimeters : 1 meter = 100 cm : 10 meters = 1000 cmArea of a rectangle = length x width.70 = 1000 x width : width = 70/1000 = 0.07 cmPerimeter of a rectangle = 2 (length + width) = 2(1000 + 0.07) = 2 x 1000.07 = 2000.14 cm = 2000.14/100 = 20.0014 meters.
Area = 150 square yards. A=l x w; Perimeter = 2(w + l): l = 6w; 2(w+6w)=2w + 12 w; 14w = 70; w=70/14=5; 6w = 30; therefore 5 x 30 = 150.
34 feet
(70/10) m
Assuming that you have a rectangle shaped area, 20 yards long by 15 yards wide, and you want to completely enclose the area with the fencing, then you have a problem where you need to find the perimeter of a rectangle. Perimeter = 2 * Length + 2 * Width Perimeter = 2 * (20 yd) + 2 * (15 yd) = 40 yd + 30 yd = 70 yards
Perimeter = l + l + w + w, where l is the length and w is the width.P = 2l + 2wIn this case: 70 = 2(2) + 2w70 = 4 + 2w66 = 2ww = 33So the width of the rectangle is 33 feet.
If the length to width ratio is 4 to 5 then the length to width ratio is 4 to 5no matter what the perimeter. If the perimeter is 70 feet then the sides are 15.555... and 19.444... feet respectively.
The width is 34 feet. Since you know the length (l) of one side is 1 foot, and the perimeter is 70 feet, then each of the longest sides is 70/2-l