If volume of two similar figures are 729 mm cubed plus 2744 mm cubed if the surface area of the larger figure is 392 mm squared what is the surface area of the smaller figure?

Answer 1

To find the surface area of the smaller figure, we can use the relationship between the volumes and surface areas of similar figures. The volume ratio of the larger figure to the smaller figure is ( \frac{2744}{729} = \left(\frac{a}{b}\right)^3 ), where ( a ) is the linear dimension of the larger figure and ( b ) is that of the smaller figure. Taking the cube root gives the linear scale factor ( \frac{a}{b} = \frac{14}{9} ). The surface area ratio, which is the square of the scale factor, is ( \left(\frac{14}{9}\right)^2 = \frac{196}{81} ). Given the surface area of the larger figure is 392 mm², the surface area of the smaller figure is ( 392 \times \frac{81}{196} = 162 ) mm².