If the volumes are 343 mm3 and 512 mm3 then these represent a three dimensional object. The equivalent ratio of a single dimension is ³√343 : ³√512 = 7 : 8.
Areas are proportional to the square of the single dimension, namely 72 : 82 = 49 : 64.
Let A be the surface area of the smaller figure.
As the areas are proportional then A/192 = 49/64
Therefore A = 192 x 49/64 = 147 mm2.
figures with the same volume does not have the same surface area.
It is the measurement units for the surface area.
20cm squared.
450 mm2 Ratio of areas is the square of the ratio of lengths. Ratio of volumes is the cube of the ratios of lengths. If the volumes are in the ratio of 512 to 3375, then the lengths are in the ratio of: 3√512 : 3√3375 = 8 : 15 ⇒ ratios of areas: 82 : 152 = 64 : 225 ⇒ as smaller has surface area of 128 mm2, the larger has: surface_area = (128 ÷ 64) x 225 mm2 = 450 mm2
The surface area of a (closed) cylinder equals the surface area of both bases (the top and bottom), i.e. pi x radius squared (first base) + pi x radius squared (second base), plus the lateral surface area (the surface area of the curved side), i.e. circumference (pi x diameter) x height. Inserting the numbers: SA = pi x (2 m.) squared + pi x (2 m.) squared + pi x 4 m. x 6 m. = pi x 4 m. squared + pi x 4 m. squared + pi x 24 m. squared = 8 x pi m. squared + 24 x pi m. squared = 32 x pi meters squared.
you put: a squared over b squared = surface area of the smaller solid over surface area of the bigger solid
v
To find the surface area of the smaller figure, we can use the relationship between the volumes and surface areas of similar figures. The volume ratio of the larger figure to the smaller figure is ( \frac{2744}{729} = \left(\frac{a}{b}\right)^3 ), where ( a ) is the linear dimension of the larger figure and ( b ) is that of the smaller figure. Taking the cube root gives the linear scale factor ( \frac{a}{b} = \frac{14}{9} ). The surface area ratio, which is the square of the scale factor, is ( \left(\frac{14}{9}\right)^2 = \frac{196}{81} ). Given the surface area of the larger figure is 392 mm², the surface area of the smaller figure is ( 392 \times \frac{81}{196} = 162 ) mm².
On a very basic level, surface area and volume are both ways to measure 3-demensional figures.
Notice the exponents in these two statements.Those little tiny numbers tell the whole big story:(the ratio of the surface areas of similar figures) = (the ratio of their linear dimensions)2(the ratio of the volumes of similar solids) = (the ratio of their linear dimensions)3
The surface area to volume ratio decreases - assuming the shape remains similar.
The ratio of the surface areas of two similar figures is equal to the square of the ratio of their corresponding linear dimensions. Given the surface areas are 27 and 1331, the ratio of their corresponding linear dimensions is the square root of ( \frac{1331}{27} ). Since the volume ratio is the cube of the linear dimension ratio, we can find the larger volume by calculating ( \frac{1331}{27} ) and then multiplying the smaller volume (18) by the cube of that ratio. The larger volume is therefore ( 18 \times \left(\frac{1331}{27}\right)^{\frac{3}{2}} = 486 ).
The volume is cubed and the surface area is squared.
figures with the same volume does not have the same surface area.
Surface area is squared. Only volume is cubed.
It is the measurement units for the surface area.
If many smaller cubes are combined to form a larger cube, then the surface area of the large cube is: 6 x (length of one side squared)