x^2+y^4=10x+7 @ (1,-2)
Rearrange to isolate y.
y=(-x^2+10x+7)^(1/4)
Take derivative.
y'=(1/4)*((-x^2+10x+7)^(-3/4))*(-2x+10)
y'=(-2x+10)/4*(-x^2+10x+7)^(3/4)
Sub in x=1.
y'=8/2*(16)^(3/4)
y'=2/8
y'=1/4
y'=m=slope=1/4
Sub m and (1,-2) into linear equation (tangent line).
m*(x-x1)=y-y2
(1/4)(x-1)=y+2
Isolate y.
Equation of tangent line: y=(1/4)x-(9/4).
The third question is unclear.
Although normally it is the line that is considered to be tangent to an arc, an arc can be tangent to infinitely many lines and so the answer to the question is: in infinitely many ways.
parallel lines never touch, never get any closer or any further apart. tangent lines touch at one point
dy/dx = m
You can have a tangent line for every point on a circle, so the answer is theoretically infinite.
No because the slope of the second equation is 1/4 and for it to be perpendicular to the first equation it should be 1/3
no
3
answer is 1
Although normally it is the line that is considered to be tangent to an arc, an arc can be tangent to infinitely many lines and so the answer to the question is: in infinitely many ways.
parallel lines never touch, never get any closer or any further apart. tangent lines touch at one point
dy/dx = m
Two lines tangent to a circle at the endpoints of its diameter are parallel. See related link for proof.
You can have a tangent line for every point on a circle, so the answer is theoretically infinite.
I assume the question should be y = -2x + 5? The equation of a line that is parallel to that line is any line that begins 7 = -2x ... after the -2x any number may be added or subtracted. Parallel lines have the same slope. In the original equation, the slope is -2.
No. In the coordinate plane, for example, they would result in different lines.
No because the slope of the second equation is 1/4 and for it to be perpendicular to the first equation it should be 1/3
A secant line touches a circle at two points. On the other hand a tangent line meets a circle at one point.