No because the slope of the second equation is 1/4 and for it to be perpendicular to the first equation it should be 1/3
No, the two lines are not perpendicular.
The slopes of perpendicular lines are negative reciprocals.[ y = -3x + 2 ] is perpendicular to [ y = x/3 plus any number ].
They are perpendicular lines because the slopes are 3/4 and -4/3 respectively.
No.
No. they are parallel, since the slopes are both equal in this case 3. To be perpendicular the product of the slopes of both lines is equal to -1 (i.e., m1*m2 = -1).
No, the two lines are not perpendicular.
The slopes of perpendicular lines are negative reciprocals.[ y = -3x + 2 ] is perpendicular to [ y = x/3 plus any number ].
They are perpendicular lines because the slopes are 3/4 and -4/3 respectively.
No.
No. they are parallel, since the slopes are both equal in this case 3. To be perpendicular the product of the slopes of both lines is equal to -1 (i.e., m1*m2 = -1).
8
y = 1/3x+4
3x+y = 4 y = -3x+4 Perpendicular slope: 1/3
The question is not quite clear but one equation will be y = 3x+6 and the other equation will have a slope of minus 1/3
one is y=3x+3 so is y=3x+5
4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3
The x and y axes on the Cartesian plane are perpendicular to each other at the point of origin