3x + 2 = 3x + 6 This is not possible.
There are an infinite number of lines that are all parallel to [ y = 3x + 6 ].Here are ten of them to get you started:y = 3x - 1y = 3xy = 3x + 1y = 3x + 2y = 3x + 3y = 3x + 4y = 3x + 5y = 3x + 5.99y = 3x + 6.001y = 3x + 7.etc.
12x - 9y = 6, 12x + 20y = 64 29y = 58 y = 2 x = 2
Multiply first equation by 3: 9x + 15y = 63Add that and second equation: 19y = 57Divide by 19: y = 3, so x = 2
what is a slope
3x+5y=48 5y=48-3x-3x+5y=12 -3x+(48-3x)=12-6x=-36x=65y=48-3(6)5y=30y=6(6,6)
x = 2, y = 3
If: 3x+5y = 6 Then: y = -3/5x+6/5 which means it has a slope of -3/5 Parallel equation: y-1 = -3/5(x-3) => 5y-5 = -3(x-3) => 5y = -3x+14 Or as: 3x+5y = 14
The given expressions are: 5x + 5y = 30 3x - 5y = -30 Combine both equations to get: 5x + 3x + 5y - 5y = -30 + 30 8x = 0 Then: 8x/8 = 0/8 x = 0 Substitute that value for either of the expressions to get: 5(0) + 5y = 30 5y = 30 y = 30/5 y = 6 Therefore, the coordinates are x = 0 and y = 6.
Known equation: 3x+5y = 6 or y = -3/5x +6/5 Slope of equation: -3/5 Slope of parallel equation: -3/5 Parallel equation: y-1 = -3/5(x-3) => 5y = -3x+14 Parallel equation in its general form: 3x+5y-14 = 0
y = mx + b (where m is the slope) So -3x - 5y = 6 (add 3x to both sides) -5y = 3x + 6 (divided both sides by -5) y = -3/5x - 6/5 Slope is -3/5 or -.6
3x + 2 = 3x + 6 This is not possible.
There are an infinite number of lines that are all parallel to [ y = 3x + 6 ].Here are ten of them to get you started:y = 3x - 1y = 3xy = 3x + 1y = 3x + 2y = 3x + 3y = 3x + 4y = 3x + 5y = 3x + 5.99y = 3x + 6.001y = 3x + 7.etc.
-3x = 3 + y 3 + y - 5y = -21 -4y = -24 y = 6 x = -3
5y+8 = 7y-6 5y-7y = -6-8 -2y = -14 y = 7
p + q + r = (2x - 9y) + (5y + 6 - 4x) + (3x + 3y - 5) = x - y + 1
12x - 9y = 6, 12x + 20y = 64 29y = 58 y = 2 x = 2