x
If WXYZ is a square, then all four sides are equal in length, meaning WX = XY = YZ = ZW. Additionally, each angle must measure 90 degrees, ensuring that the corners are right angles. The diagonals WX and YZ must also be equal in length and bisect each other at right angles. Finally, the diagonals should intersect at the midpoint of each diagonal.
y(z+x) + 4(x+z)
There appear to be 10 terms in the determinant. A determinant can only have a perfect number of terms. So something has gone wrong with the question. 1: x2 plus 1 2: xy 3: xz 4: xy 5: y2 plus 1 6: yz 7: 1 plus x2 plus y2 plus z2 8: xz 9: yz 10: z2 plus 1
10 cm
x
The possible combinations of pairs that can be formed using the keywords xy, xz, and yz are: xy, xz, and yz.
The only common factor to all terms is yz. → xy³z² + y²z + xyz = yz(xy²z + y + x)
2(xy+xz+yz)=100 xy+xz+yz=50 or x(y+z)+yz=50 x=2, y=4, z=7
If WXYZ is a square, which statements must be true? Check all that apply: ANSWERS (apex): angle W is supplementary to angle Y. angle W is congruent to angle Y. angle W is a right angle. WXYZ is a parallelogram WX ≅ XY
Let's denote the length of leg YZ as x. Since leg XY is twice as long as leg YZ, its length would be 2x. The formula for the area of a right triangle is A = 1/2 * base * height. In this case, the base is YZ (x) and the height is XY (2x). Given that the area is 36 cm², we can set up the equation 1/2 * x * 2x = 36. Solving for x, we get x = 6. Therefore, the length of leg XY (2x) is 2 * 6 = 12 cm.
y(z+x) + 4(x+z)
8.3
There appear to be 10 terms in the determinant. A determinant can only have a perfect number of terms. So something has gone wrong with the question. 1: x2 plus 1 2: xy 3: xz 4: xy 5: y2 plus 1 6: yz 7: 1 plus x2 plus y2 plus z2 8: xz 9: yz 10: z2 plus 1
If the lengths of the edges are x, y and z units, then the total surface area is 2*(xy + yz + zx).
I am assuming that you are in a three dimensional world. Then the three planes of projection would be the xy plane, the xz plane, and the yz plane.
10 cm