x
y(z+x) + 4(x+z)
There appear to be 10 terms in the determinant. A determinant can only have a perfect number of terms. So something has gone wrong with the question. 1: x2 plus 1 2: xy 3: xz 4: xy 5: y2 plus 1 6: yz 7: 1 plus x2 plus y2 plus z2 8: xz 9: yz 10: z2 plus 1
10 cm
I am assuming that you are in a three dimensional world. Then the three planes of projection would be the xy plane, the xz plane, and the yz plane.
x
The possible combinations of pairs that can be formed using the keywords xy, xz, and yz are: xy, xz, and yz.
The only common factor to all terms is yz. → xy³z² + y²z + xyz = yz(xy²z + y + x)
2(xy+xz+yz)=100 xy+xz+yz=50 or x(y+z)+yz=50 x=2, y=4, z=7
If WXYZ is a square, which statements must be true? Check all that apply: ANSWERS (apex): angle W is supplementary to angle Y. angle W is congruent to angle Y. angle W is a right angle. WXYZ is a parallelogram WX ≅ XY
Let's denote the length of leg YZ as x. Since leg XY is twice as long as leg YZ, its length would be 2x. The formula for the area of a right triangle is A = 1/2 * base * height. In this case, the base is YZ (x) and the height is XY (2x). Given that the area is 36 cm², we can set up the equation 1/2 * x * 2x = 36. Solving for x, we get x = 6. Therefore, the length of leg XY (2x) is 2 * 6 = 12 cm.
8.3
y(z+x) + 4(x+z)
There appear to be 10 terms in the determinant. A determinant can only have a perfect number of terms. So something has gone wrong with the question. 1: x2 plus 1 2: xy 3: xz 4: xy 5: y2 plus 1 6: yz 7: 1 plus x2 plus y2 plus z2 8: xz 9: yz 10: z2 plus 1
If the lengths of the edges are x, y and z units, then the total surface area is 2*(xy + yz + zx).
10 cm
I am assuming that you are in a three dimensional world. Then the three planes of projection would be the xy plane, the xz plane, and the yz plane.