2xy + 4x + 8y + 16 = 2[xy + 2x + 4y + 8] = 2[x(y + 2) + 4(y + 2)] = 2(y + 2)(x + 4)
2+2y+x+xy=(x+2)(y+1)
x(y - 10) + 6y
x^2 - xy + y^2
There are a few ways to isolate a variable. First, add or subtract anything to get a monomial on one side containing the variable. Then divide by anything that is being multiplied to the variable. Here is an example: xy-4z=2z-4y solving for x xy=(2z+4z)-4y xy=6z-4y x=(6z-4y)/y
( 2xy - 4x ) + ( 8y - 16)2 ( xy - 2x ) + 2 ( 4y - 8 ) Answer
2 (2x2 + 2x + xy + y ) it's 2 (2x + y)(x + 1) if you're doing A+
In order to combine terms, the variable(s) must be the same and the exponent(s) must be the same on the variables. Since you have an x2 term, x term, xy term and y term, none of the terms can be combined. So, the answer is: x2 + 4x + xy + 4y. The only thing you could do in this problem is to factor out a 4 from the 4x & 4y so another way to write this is: x2 + xy + 4(x + y).
4x-y2=2xy 2x ? y5 if its plus its 7 xy
-1
2xy + 4x + 8y + 16 = 2[xy + 2x + 4y + 8] = 2[x(y + 2) + 4(y + 2)] = 2(y + 2)(x + 4)
2+2y+x+xy=(x+2)(y+1)
x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)
2-4x is an expression - neither an equation nor an inequality. An expression does not have xy coordinates.
(x-y) + (xy - 1) = (x - 1)(y + 1)
xy plus 2x plus 4y plus 8 or (xy+2x) + (4y+8) or x(y+2) + 4(y+2) or (x+4)(y+2)
(x2 - xy + y2)(x + y)