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Given y varies directly as x and y equals 125 when x equals 25what is the value of y when x equals 2?

y varies directly as x so y = cx for some constant c. y = 125 when x = 25 so 125 = c*25 so that c = 5 ie the relationship is y = 5x Then when x = 2, y = c*x = 5*2 = 10


If y varies directly with x and y equals 10 when x equals 5 what is the value of k?

We write y=kx since y varies directly as x. Now we know if x is 5, y is 10. so we write 10=5k so k=2


What is the constant of variation k if x .5 and y 1 Assume y varies directly as x?

If y varies directly as x then k = 2.


What is the difference of place value of 5 in 25.35?

the value and place value of 2 in 25 is tens and 20. the value and place value of 5 in 25 is units/ones and 5.


Find an equation of variation where y varies directly as x and y equals 2 when x equals 10 find y when x equals -25?

y = -5


Find the value of-5-(20)?

To find the value of -5 - (20), you simply subtract 20 from -5. This can be rewritten as -5 - 20, which equals -25. Therefore, the value is -25.


What is the numerical value of 5x5x5x5?

5 x 5 = 25 25 x 25 = 625


R varies directly as s find r when s equals 7 and k equals 5?

Since r varies directly with s, we have r = ks (replace k with 5 and s with 7) r = (5)(7) r = 35


When y is 10 what is the value of 5y - 25?

It is: (5*10)-25 = 25


What is the difference between the face value and place value of 5 in 25?

The face value is 5, the place value is units.


1 5 of 25?

1/5 of 25 is equal to 25 divided by 5, which equals 5. This means that if you take one-fifth of the number 25, you are left with the value of 5.


What is the value of 5 in 25?

0.2, 20% or 1/5