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If y varies directly as x squared find k when y equals 16 and x equals -4?
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If the equation of variation where y varies directly as x One pair of values is y equals 80 when x equals 40?
Since ( y ) varies directly as ( x ), we can express this relationship as ( y = kx ), where ( k ) is the constant of variation. Given the values ( y = 80 ) when ( x = 40 ), we can find ( k ) by substituting these values into the equation: ( 80 = k(40) ). Solving for ( k ) gives ( k = 2 ). Therefore, the equation of variation is ( y = 2x ).
How do you prove that x and y are directly proportional with the equation Y equals 8X-3?
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X varies directly with y and inversely with z. x 5 when y 10 and z 5. Find x when y 20 and z 10x varies directly with y and inversely with z. x 5 when y 10 and z 5. Find x when y 20 and z 10x varies d?
Since ( x ) varies directly with ( y ) and inversely with ( z ), we can express this relationship as ( x = k \frac{y}{z} ), where ( k ) is a constant. Given that ( x = 5 ) when ( y = 10 ) and ( z = 5 ), we can find ( k ): [ 5 = k \frac{10}{5} \implies k = 2. ] Now, to find ( x ) when ( y = 20 ) and ( z = 10 ): [ x = 2 \frac{20}{10} = 4. ] Thus, ( x ) equals 4.
What is the formula for the perimeter of a square varies directly as the length of its side?
The formula for the perimeter ( P ) of a square is given by ( P = 4s ), where ( s ) is the length of one side. This shows that the perimeter varies directly with the side length; as the side length increases, the perimeter increases proportionally. Therefore, if the side length doubles, the perimeter also doubles, maintaining a consistent ratio.
If w varies directly as 2x-1 and w equals 9 when x equals 2 find x when w equals 15?
The phrase "varies directly as" means that there is a number k such that w = k(2x - 1). From the results given for w = 9 when x = 2, 9 = k(4 - 1), or k = 3. Then when w is 15, 15 = 3(2x - 1), or 15 = 6x - 3, or 6x = 15 + 3, or x = 18/6 = 3.
If y varies directly as x squared find k when y equals 16 and x equals -4?
20
If the equation of variation where y varies directly as x One pair of values is y equals 80 when x equals 40?
Since ( y ) varies directly as ( x ), we can express this relationship as ( y = kx ), where ( k ) is the constant of variation. Given the values ( y = 80 ) when ( x = 40 ), we can find ( k ) by substituting these values into the equation: ( 80 = k(40) ). Solving for ( k ) gives ( k = 2 ). Therefore, the equation of variation is ( y = 2x ).
X varies directly with y and inversely with z x equals 125 when y equals 5 and z equals 4 Find x when y equals 4 and z equals 5?
Given x=k1y and x=k2/z x=125 ,y=5 then k1=25 x=125 , z=4 then k2=125(4)=500 If y=4 ,z=5 then x=25y = 100
How do you prove that x and y are directly proportional with the equation Y equals 8X-3?
11
X varies directly with y and inversely with z. x 5 when y 10 and z 5. Find x when y 20 and z 10x varies directly with y and inversely with z. x 5 when y 10 and z 5. Find x when y 20 and z 10x varies d?
Since ( x ) varies directly with ( y ) and inversely with ( z ), we can express this relationship as ( x = k \frac{y}{z} ), where ( k ) is a constant. Given that ( x = 5 ) when ( y = 10 ) and ( z = 5 ), we can find ( k ): [ 5 = k \frac{10}{5} \implies k = 2. ] Now, to find ( x ) when ( y = 20 ) and ( z = 10 ): [ x = 2 \frac{20}{10} = 4. ] Thus, ( x ) equals 4.
When a 6 and bb22 c33. If x varies directly with b and inversely with a which equation models thr situation?
If ( x ) varies directly with ( b ) and inversely with ( a ), the relationship can be expressed mathematically as ( x = k \frac{b}{a} ), where ( k ) is a constant of proportionality. In this case, given ( a = 6 ) and ( b = 22 ), the equation modeling the situation would be ( x = k \frac{22}{6} ).
What is the formula for the perimeter of a square varies directly as the length of its side?
The formula for the perimeter ( P ) of a square is given by ( P = 4s ), where ( s ) is the length of one side. This shows that the perimeter varies directly with the side length; as the side length increases, the perimeter increases proportionally. Therefore, if the side length doubles, the perimeter also doubles, maintaining a consistent ratio.
If x varies jointly as y and the square as z and x equals 40 when y equals 20 and z equals 2 find x when y equals 30 and z equals 3?
As x ∝ yz2 then x = kyz2 where k is a constant. Substituting the given figures, 40 = k*20*22 = 80k Then k = ½ and the formula is, x = ½yz2 So, x = ½ * 30 *32 = 135
What helps determine the capillary density in a given tissue?
Capillary density within tissues varies directly with tissues' rates and metabolism.
How many distinct strings of factors are there for a given number?
It varies with each given number.
What is true about soft money today?
it may not be given directly to political parties
