To provide the variable expression when ( n ) equals 6, we first need to know the specific variable expression in question. However, if we assume a general expression like ( 3n + 2 ), substituting ( n ) with 6 would yield ( 3(6) + 2 = 18 + 2 = 20 ). Please provide the specific expression for a more tailored response.
The general idea is to solve one of the equations for one variable - in terms of the other variable or variables. Then you can substitute the entire expression into another equation or other equations; as a result, if it works you should end up having one less equation, with one less variable.
The evaluate a algebraic math expression you first must substitute a number for each variable. Then you must perform the operation in the correct order.
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
Not necessarily.A variable can hold other types of values, not just numbers. For example, a variable can hold a date, a text (also know as "string"), a boolean (true or false) value, etc. In object-oriented programming, you basically make up your own data types.An array variable can hold several related values. The individual values are usually distinguished by a number, called a subscript. (In other words, you have the first element, the second element, etc. in the array.)
in the first column on the left
yes
To provide the variable expression when ( n ) equals 6, we first need to know the specific variable expression in question. However, if we assume a general expression like ( 3n + 2 ), substituting ( n ) with 6 would yield ( 3(6) + 2 = 18 + 2 = 20 ). Please provide the specific expression for a more tailored response.
The general idea is to solve one of the equations for one variable - in terms of the other variable or variables. Then you can substitute the entire expression into another equation or other equations; as a result, if it works you should end up having one less equation, with one less variable.
No. To evaluate a variable, you simply take its value. When you assign a value to a variable, the evaluation of that operation is the value of the variable after assignment. There is no calculation required to evaluate a variable, unless that calculation is part of the right-hand operand of an assignment operation, in which case the calculation is evaluated first and the result of that evaluation (the value) is then assigned to the variable which is then evaluated.
The evaluate a algebraic math expression you first must substitute a number for each variable. Then you must perform the operation in the correct order.
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
Write an expression consisting of up to three terms:One term in which the key variable is squared,one term with a multiple of the variable, anda constant.The first of these MUST be present. The three terms must be added or subtracted.
the first number in an ordered pair is the x coordinate it is one of the values that the independent variable has taken on
By shifting the values in an array, you are moving a key's value to the previous key. The very first key's value is obliterated. By shifting all values in the array, all keys will have a value of NULL. Unsetting a variable is entirely different -- performing a variable unsetting causes the variable to have a value of NULL, as if it was never set.
the first number in an ordered pair is the x coordinate it is one of the values that the independent variable has taken on
In the first expression the value is 91 times as large as it is in the second.