The sample space consists of all the possible outcomes. A flip of a coin has 2 outcomes, H,T. The total number of outcomes for 6 flips are 26 or 64.
5 outcomes if the sequence is ignored. 24 = 16 outcomes in all.
50%. there are only 2 choices heads or tails and that doesn't change no matter how many times you flip the coin
Highly probable - APEX :)
The probability of the coin landing "head" side up is 50/50, meaning it could land "head" side up or "tail" side up. The odds of any single coin flip are always the same, no matter what happened on the previous tosses -- provided the coin is not a "double-head" (or "double-tail") "trick" coin
The sample space consists of all the possible outcomes. A flip of a coin has 2 outcomes, H,T. The total number of outcomes for 6 flips are 26 or 64.
5 outcomes if the sequence is ignored. 24 = 16 outcomes in all.
50%. there are only 2 choices heads or tails and that doesn't change no matter how many times you flip the coin
The probability of getting all heads if you flip a coin three times is: P(HHH) = 1/2 ∙ 1/2 ∙ 1/2 = 1/8. The probability of getting all tails if you flip a coin three times is: P(TTT) = 1/2 ∙ 1/2 ∙ 1/2 = 1/8. The probability of getting all heads or all tails if you flip a coin three times is: P(HHH or TTT) = P(HHH) + P(TTT) = 2/8 = 1/4.
Highly probable - APEX :)
1/8. The probability of flipping a coin three times and it landing on head is 1/2, as a coin only has two sides. You flip a coin three times, therefore the answer is (1/2)^3 = 1/8.
The probability of the coin landing "head" side up is 50/50, meaning it could land "head" side up or "tail" side up. The odds of any single coin flip are always the same, no matter what happened on the previous tosses -- provided the coin is not a "double-head" (or "double-tail") "trick" coin
Do you mean what are all the possible outcomes? Or what is the probability of a certain outcome? Need a little more information.
Each flip has two possible outcomes and they are independent events, so there are 24 = 16 possible results. Of these, only 2 (HHHH, TTTT) are the same 4 each time, Thus: probability = 2/16 = 1/8
If each coin is a different color, then there are 32 possible outcomes. If you can't tell the difference between the coins, and you're just counting the number of heads and tails, then there are 6 possible outcomes: 5 heads 4 heads 3 heads 2 heads 1 heads all tails
There are technically 8 possible outcomes if you are talking about the side of the coin it lands on. Each coin has 2 possible outcomes (landing on heads and landing on tails). To figure out the number of outcomes for all the coins you multiply the outcomes for all of the coins together: 2 X 2 X 2= 8.
The probability that the coin lands on the heads ones: 1/2Two times (1/2)^2 = 1/4Five times (1/2)^5 = 1/32 (so 1 in 32 attempts)n times (1/2)^n