What do you mean by "largest" ???
Do you want the widest rectangle ?
The longest rectangle ?
How about the rectangle with the most area ?
The length can be anything less than 20 ft, and the width can be anything less than 20 ft.
Any of those shapes will have an area greater than zero.
The rectangular garden with the greatest possible area is a square, 10 ft x 10 ft.
Its area is 100 square feet.
A square 14 ft on a side.
To find the dimensions of a rectangle with the largest perimeter using 100 feet of fencing, we can express the perimeter ( P ) of a rectangle in terms of its length ( l ) and width ( w ) as ( P = 2l + 2w ). Since the total amount of fencing is 100 feet, we set up the inequality ( 2l + 2w \leq 100 ). Simplifying this gives ( l + w \leq 50 ). The dimensions that maximize the area (which is a related concept) would be when ( l = w = 25 ) feet, creating a square shape.
15 yd by 15 yd square (educated guess???)
The largest pen you can make is a circle with a circumference of 100 meters.Its diameter is 31.83 meters, and its area = 795.77 square meters.It's a lot easier to just go with a square ... the largest area you can make with straight sides.Use the 100 meters of fence to enclose a (25 x 25) square. The area is 625 square meters.
To maximize the area of a rectangle with a fixed perimeter, the rectangle should be a square. Given 14 inches of string, the perimeter ( P ) is 14, so each side of the square would be ( \frac{14}{4} = 3.5 ) inches. The area ( A ) of the square is then ( A = 3.5 \times 3.5 = 12.25 ) square inches. Thus, the largest rectangular area that can be enclosed is 12.25 square inches.
A square 14 ft on a side.
10' X 10' = 100 sqft. The more you deviate from a square, the smaller the area will be. If you change the sides by 1 foot, you are left with 9 X 11 which is only 99 sqft. If you make the rectangle long and narrow, 19 X 1 is only 19 sqft.
280cm???
The largest and heaviest Fencing weapon is the Epee
15 yd by 15 yd square (educated guess???)
The largest pen you can make is a circle with a circumference of 100 meters.Its diameter is 31.83 meters, and its area = 795.77 square meters.It's a lot easier to just go with a square ... the largest area you can make with straight sides.Use the 100 meters of fence to enclose a (25 x 25) square. The area is 625 square meters.
leon paul is the largest in Britain situated in London
Camp Nou (Barcelona F.C) see its dimensions at wikipedia (it's the largest legal dimensions)
Lowes has the best deal around on composite fencing. They do not have the largest selection, but they make up for it in price. Composite fencing has different maintenance levels based on brands. Timbertech and Trex are the brand leaders in the composite fencing industry.
A square of side 5½ inches gives an area of 30.25 in2. This is maximum area. Rectangle 6 x 5 has area 30, 7 x 4 has area 28 etc etc.
A cube.
Find the dimensions of the rectangular field of maximum area which can be enclosed with 400 feet of fence. . Let w = width of field then (400-2w)/2 = length of field (200-w) = length of field . area = w(200-w) area = 200w-w^2 area = -w^2+200w . Looking at the coefficient for the w^2 term, we see that it is negative. This indicates that the parabola opens downward and finding the vertex will give you the "maximum". . Standard vertex form is: y= a(x-h)^2+k where (h,k) is the vertex . Convert our equation into that form by "completing the square": area = -w^2+200w area = -(w^2-200w) area = -(w^2-200w+10000) + 10000 area = -(w-100)^2 + 10000 . From the above, we see that the vertex is: (h,k) = (100, 10000) . This says that when the width=100 feet, the area will be maximized at 10000 square feet. . Solution: width = 100 feet length = 200-w = 200-100 = 100 feet