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If there are n people, you have n*(n-1)/2 handshakes
That gives the equation n*(n-1)/2 = 66
or n*(n-1) = 132
n2 - n - 132 = 0
(n - 12)*(n + 11) = 0
The solution to this quadratic are n = 12 or n = -11
Since the number of people cannot be negative, n must be 12.
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If there are 100 people at a party and they all shake hands once how many hand shakes will there be?
4950
If 5 people meet and all shake each others hands how many handshake will there be?
20 ; 80 (assuming they shake both hands)
How many handshakes are there if 200 people all shake hands?
4950
If 99 people handshake how many handshakes will there be?
Since it takes two to shake hands, no odd number of people can handshake, since one must be left out. Therefore 99 people cannot shake hands. Unless "handshake" means something unusual here, which seems unlikely, as it is the only handshaking activity where you can count the handshakes. * * * * * What utter nonsense! 3 people: A, B and C can shake hands. AB shake hands, AC shake hands and BC shake hands. And the last time I looked 3 was still classified as an odd number. The correct answer is 99*98/2 = 4851
There are 9 people they all shake hands how many hand shakes are there?
36. Everybody shakes 8 hands but each shake counts for 2 people. So 9*8/2=36.
If there are 100 people at a party and they all shake hands once how many hand shakes will there be?
4950
there are 3 people at a party if each person mis shake hands with every person at the party exactly once how many handshakes will there be?
So, there will be 3 handshakes among the 3 people at the party.
There are 6 people at a party If each person must shake hands with every other person at the party exactly once how many handshakes will there be?
15
If There are 5 people at a party Each person must shake hands once with every other person at the party How many handshakes does it take to do this?
10 times
If There are 3 people at a party If each person must shake hands with every other person at the party exactly once how many handshakes will there be?
3. AB, BC and CA.
There are 6 people at a party If each person must shake hands with every other person at the party exactly once, how many handshakes will there be?
The first person must shake hands with 5 other people. The next must shake hands with 4 other people, since you exclude the first person. Keep going and you'll find that there will be 5+4+3+2+1=15 handshakes. Numbers like this are called triangular numbers.
How many handshakes are there if 4 people shake hands?
12
If 5 people meet and all shake each others hands how many handshake will there be?
20 ; 80 (assuming they shake both hands)
How many handshakes are there if 200 people all shake hands?
4950
If at a party there are twelve people present Everyone has to shake hands exactly once with every other person How many handshakes are necessary?
Sixty-six unique, distinct handshakes.
If 99 people handshake how many handshakes will there be?
Since it takes two to shake hands, no odd number of people can handshake, since one must be left out. Therefore 99 people cannot shake hands. Unless "handshake" means something unusual here, which seems unlikely, as it is the only handshaking activity where you can count the handshakes. * * * * * What utter nonsense! 3 people: A, B and C can shake hands. AB shake hands, AC shake hands and BC shake hands. And the last time I looked 3 was still classified as an odd number. The correct answer is 99*98/2 = 4851
There are 9 people they all shake hands how many hand shakes are there?
36. Everybody shakes 8 hands but each shake counts for 2 people. So 9*8/2=36.
