The diagonal can be found by taking length^2+width^2=diagonal^2
13^2=x^2+(x+7)^2
169 = x2 + x2 + 14x + 49
120 = 2x2 + 14x
x2 + 7x - 60 = 0
now just factor, and you have the answer. It's the positive x value.
The diagonal is 26cm
The diagonal length is about 18.44 inches.
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
Diagonal = 18.867 feet.
If the only known fact is the length of the diagonal then the width and length of the rectangle CANNOT be determined. The diagonal could be that of a square, or of a rectangle that is very long but quite narrow. Consequently at least one more fact is required such as; the dimension of either the length or the width, or the angle that the diagonal makes to the base of the rectangle or even the area of the rectangle.
The width will be 30cm
The diagonal is 26cm
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
The length of the diagonal is about 16.03 feet.
Width is 5.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
The diagonal is 20.
The diagonal length is about 18.44 inches.
62 +82 = 102 so 6 and 8
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
Diagonal = 10 meters.
The diagonal is 3.61cm