The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
If the only known fact is the length of the diagonal then the width and length of the rectangle CANNOT be determined. The diagonal could be that of a square, or of a rectangle that is very long but quite narrow. Consequently at least one more fact is required such as; the dimension of either the length or the width, or the angle that the diagonal makes to the base of the rectangle or even the area of the rectangle.
infinitely far
Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764
According to the given length & width, the diagonal must be 15 cm.So,2X - 11 = 152X = 26X = 13
The width and the length are independent. You can have a very long rectangle which is very wide or not wide at all. They are related when it comes to calculating area or perimeter of the rectangle. Perhaps that is what you meant?
If the only known fact is the length of the diagonal then the width and length of the rectangle CANNOT be determined. The diagonal could be that of a square, or of a rectangle that is very long but quite narrow. Consequently at least one more fact is required such as; the dimension of either the length or the width, or the angle that the diagonal makes to the base of the rectangle or even the area of the rectangle.
infinitely far
15 cm Solved through Pythagoras' theorem.
Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764
-- A rectangle has no 'formula'. -- The length of the diagonal is 24feet 10.62inches (rounded)
If the length of a rectangle is 12 and the width of the rectangle is 16, by the Pythagorean theorem we know that one diagonal is 20 units long. You can draw two diagonals within a rectangle, so the length of both diagonals together is 20+20 = 40 units.
15 cm for the diagonal.
A rectangle is a four-sided figure with two long sides and two short sides. The two long sides are the length of the rectangle. The two short sides are the width of the rectangle.
Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters
Area of a rectangle= Length * width Length= 5cm Width= 1cm Area=5cm *1cm =5cm2
According to the given length & width, the diagonal must be 15 cm.So,2X - 11 = 152X = 26X = 13
The diagonal creates a right angled triangle with one pair of long and short sides - the diagonal is the hypotenuse. We know the angle between the long side (adjacent) and hypotenuse as 42.6°; We want to find the length of the short (width) side (opposite). We can use the Tan ratio: tan = opposite/adjacent → opposite = adjacent × tan → width = 26.63 in × tan 42.6° = 24.487... in → width is 24.5 inches to the nearest tenth of an inch.