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Probability = number_of_ways_of_success / total_number_if_outcomes
As a cube has 6 faces and you have only specified that it has five numbers (1-5), one of those numbers must be repeated, thus the probability of rolling a 5 depends upon whether there is one or two sides bearing a 5:
If there is only 1 side bearing a 5, then it is 1/6
If there are 2 sides bearing a 5, then it is 2/6 = 1/3
If you meant a five sided solid, then there is no such regular solid and some face(s) would be biased to appear and it would depend upon which face has the 5.
However, an icosahedron has 20 faces and the numbers 1-5 could be repeated 4 times each, meaning that the probability of rolling a 5 would be 4/20 = 1/5.
If you had a regular pentagonal spinner, with each digit corresponding to an edge, then the probability of spinning a 5 would be 1/5.
If you mean a standard die: a cube with six sides numbers 1-6 (and the 1-5 was a typographical error), then the probability is 1/6.
What else can I help you with?
If you roll a fair number cube 30 times how many times would you expect to roll a odd number?
Type your answer here... 15
Is 15 a cube number?
No.
What is the probability of rolling less than seven when you roll 2 dice?
15/36 = 5/12
What is the probability to choose a prime number from 1 to 49?
15 from 49
A number from 17 to 15 is drawn at random p an even number express the probability as a fraction?
That leaves 3 numbers, 15, 16, 17. If you're looking for the probability of drawing an even number it would be 1/3, or 0.333.
If you roll a fair number cube 30 times how many times would you expect to roll a odd number?
Type your answer here... 15
What is the probability of rolling a number less than 7.?
With a single cube, the probability is 100%With two cubes, the probability is 15/36 = 5/12 = 412/3 %
Is 15 a cube number?
No.
What is the probability of throwing a sum of 15 on three rolls of a fair die if the first roll was a 4?
Rolling a sum of 15 on three rolls of a die, when the first roll is a 4, is the same as rolling a sum of 11 on the second and third roll. The probability of rolling 11 on two dice is 3 in 36, or 1 in 12.
What is the probability of rolling less than seven when you roll 2 dice?
15/36 = 5/12
What is the probability to choose a prime number from 1 to 49?
15 from 49
What is the probability to roll a sum of 7 with three die?
There are 216 permutations of three dice. Of these, 15 sum to 7. Therefore, the probability of rolling a sum of 7 with three dice is 15 in 216, or 5 in 72, or about 0.06944.111112113114115711612112212312471251261311321337134135136141142714314414514615171521531541551561611621631641651662112122132147215216221222223722422522623123272332342352362417242243244245246251252253254255256261262263264265266311312313731431531632132273233243253263317332333334335336341342343344345346351352353354355356361362363364365366411412741341441541642174224234244254264314324334344354364414424434444454464514524534544554564614624634644654665117512513514515516521522523524525526531532533534535536541542543544545546551552553554555556561562563564565566611612613614615616621622623624625626631632633634635636641642643644645646651652653654655656661662663664665666
A number from 17 to 15 is drawn at random p an even number express the probability as a fraction?
That leaves 3 numbers, 15, 16, 17. If you're looking for the probability of drawing an even number it would be 1/3, or 0.333.
There are 10 rolls of film in a box and 3 are defective Two rolls are selected without replacement What is the probability of selecting a defective roll followed by another defective roll?
1/15 or about 0.07
What is the probability of picking up number 15 from 1 to 20 numbers?
The probability, in a single random selection, is 1/20 or 0.05
When tossing 2 dice what is the probability of tossing a prime number?
There are 36 possibilities when rolling two six sided die. 15 of them result in a prime number (2,3,5,7,11) So the probability is 15 in 36 or a 5 in 12 chance.
What is the probability of a prime number being picked randomly from the numbers 1 through 49?
There are 15 primes from 1 to 49 (including '1').The probability is (15/49) = 30.612 %(rounded)
