60
When rolling a fair six-sided die, the probability of landing on any specific number, including 1, is ( \frac{1}{6} ). If you roll the die 60 times, you would expect to land on 1 about ( 60 \times \frac{1}{6} = 10 ) times. Therefore, you can expect to roll a 1 approximately 10 times out of 60 rolls.
When tossing two dice, the possible sums range from 2 to 12. The combinations that yield a sum of 4 are (1,3), (2,2), and (3,1), which means there are 3 favorable outcomes. Since there are a total of 36 possible outcomes when rolling two dice (6 sides on the first die multiplied by 6 sides on the second), the probability of rolling a sum of 4 is 3/36 or 1/12. Therefore, in 1000 tosses, you would expect the sum of the two dice to equal 4 about ( \frac{1000}{12} \approx 83.33 ) times, or roughly 83 times.
100/6 = 16.6 times
When rolling a fair six-sided die, the probability of rolling a three on any single roll is 1/6. If you roll the die 100 times, you can expect to see the number three about ( \frac{1}{6} \times 100 ), which is approximately 16.67 times. Therefore, you should expect to see the number three about 17 times in 100 rolls.
1/6 of 300 = 50 times.
He should expect it 100 times.
6
36 times. But also, you might get the opposite result 36 times.
36 times. But also, you might get the opposite result 36 times.
1/6 of all outcomes should be a 5. 300*1/6=50 This is the answer regardless of what you are rolling for. You would find whatever number you want and average about 50 times if you were to roll the dice 300 times. You might not get exactly 50, but it won't be far from that. There are faces on a die, and the odds of any one of those 6 numbers showing up is 1 out of 6 times. The above is only true if the dice are not rigged in any way ("loaded dice"). Now, if only one number likes to keep coming up, you might be dealing with loaded dice. In that case, the dice are made for cheating and the mathematical laws of average no longer apply.
When rolling a fair six-sided die, the probability of landing on any specific number, including 1, is ( \frac{1}{6} ). If you roll the die 60 times, you would expect to land on 1 about ( 60 \times \frac{1}{6} = 10 ) times. Therefore, you can expect to roll a 1 approximately 10 times out of 60 rolls.
never.. the highest number on a dice is a 6
100/6 = 16.6 times
When tossing two dice, the possible sums range from 2 to 12. The combinations that yield a sum of 4 are (1,3), (2,2), and (3,1), which means there are 3 favorable outcomes. Since there are a total of 36 possible outcomes when rolling two dice (6 sides on the first die multiplied by 6 sides on the second), the probability of rolling a sum of 4 is 3/36 or 1/12. Therefore, in 1000 tosses, you would expect the sum of the two dice to equal 4 about ( \frac{1000}{12} \approx 83.33 ) times, or roughly 83 times.
Well, statistically speaking, if you roll a fair six-sided die 60 times, you can expect to get a 1 about 10 times. But hey, don't get too attached to that number, probability can be a fickle friend. Just roll the dice and see what Lady Luck has in store for you!
The expected number of times is the probability x number of throws. Since you have a prob of 1/6 for a seven, then (1/6) * 160 = 26.67 times you would have success. We generally would round up the expected number of successes to the whole number 27.
The probability of rolling a four on a single roll of a fair die is 1/6. So the expected number of 4s in 450 rolls is 450*1/6 = 75.