When tossing two dice, the possible sums range from 2 to 12. The combinations that yield a sum of 4 are (1,3), (2,2), and (3,1), which means there are 3 favorable outcomes. Since there are a total of 36 possible outcomes when rolling two dice (6 sides on the first die multiplied by 6 sides on the second), the probability of rolling a sum of 4 is 3/36 or 1/12. Therefore, in 1000 tosses, you would expect the sum of the two dice to equal 4 about ( \frac{1000}{12} \approx 83.33 ) times, or roughly 83 times.
60
When rolling a fair six-sided die, the probability of landing on any specific number, including 1, is ( \frac{1}{6} ). If you roll the die 60 times, you would expect to land on 1 about ( 60 \times \frac{1}{6} = 10 ) times. Therefore, you can expect to roll a 1 approximately 10 times out of 60 rolls.
With standard dice, zero.
When rolling a fair six-sided die, the probability of rolling a three on any single roll is 1/6. If you roll the die 100 times, you can expect to see the number three about ( \frac{1}{6} \times 100 ), which is approximately 16.67 times. Therefore, you should expect to see the number three about 17 times in 100 rolls.
A fair die is a die where the probability of throwing each of the faces is equal. Dice is two or more die's.
60
He should expect it 100 times.
There are two dice with 6 side each. The probability of any single unique outcome is 1/6 * 1/6 = 1/36 Now the question becomes how many ways can you roll a 7 using two dice. It might be easiest to just show this as a table: 1 6 2 5 3 4 4 3 5 2 6 1 So there are 6 ways to roll a 7 using two dice. That means the probability of rolling a 7 is 6/36 = 1/6. Finally, to answer the question, we will multiply the probability of success (getting 7) with the number of attempts (how many times you rolled the dice). This equals 1/6 * 1000 = 166.66... or in real-life terms: 167 (remember that in real life no-one has 2.5 children)
6
36 times. But also, you might get the opposite result 36 times.
1/6 of all outcomes should be a 5. 300*1/6=50 This is the answer regardless of what you are rolling for. You would find whatever number you want and average about 50 times if you were to roll the dice 300 times. You might not get exactly 50, but it won't be far from that. There are faces on a die, and the odds of any one of those 6 numbers showing up is 1 out of 6 times. The above is only true if the dice are not rigged in any way ("loaded dice"). Now, if only one number likes to keep coming up, you might be dealing with loaded dice. In that case, the dice are made for cheating and the mathematical laws of average no longer apply.
36 times. But also, you might get the opposite result 36 times.
When rolling a fair six-sided die, the probability of landing on any specific number, including 1, is ( \frac{1}{6} ). If you roll the die 60 times, you would expect to land on 1 about ( 60 \times \frac{1}{6} = 10 ) times. Therefore, you can expect to roll a 1 approximately 10 times out of 60 rolls.
Well, statistically speaking, if you roll a fair six-sided die 60 times, you can expect to get a 1 about 10 times. But hey, don't get too attached to that number, probability can be a fickle friend. Just roll the dice and see what Lady Luck has in store for you!
With standard dice, zero.
When rolling a fair six-sided die, the probability of rolling a three on any single roll is 1/6. If you roll the die 100 times, you can expect to see the number three about ( \frac{1}{6} \times 100 ), which is approximately 16.67 times. Therefore, you should expect to see the number three about 17 times in 100 rolls.
because most dice only have numbers 1 to 6 on them