There are four of each, so 1 to 1.
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There are four 2s in a deck of cards, one of each suit.
There are four 2s in a standard deck of playing cards.
It is only because we count in tens - and 5 10 and 2 are factors.
A = (s, 2s), B = (3s, 8s) The midpoint of AB is C = [(s + 3s)/2, (2s + 8s)/2] = [4s/2, 10s/2] = (2s, 5s) Gradient of AB = (8s - 2s)/(3s - s) = 6s/2s = 3 Gradient of perpendicular to AB = -1/(slope AB) = -1/3 Now, line through C = (2s, 5s) with gradient -1/3 is y - 5s = -1/3*(x - 2s) = 1/3*(2s - x) or 3y - 15s = 2s - x or x + 3y = 17s
we have the numbers 1-10 on each of 4 suits of cards, the others are Jack,Kind and Queen. So there are fours 2s, fours 4s four 6s four 8s and four 10s which is 4x5 or 20 even cards.. There are also 20 odd ones, so 40 even and odd then add 4x3=12 J,K, Q and you have 52 cards