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There are four of each, so 1 to 1.

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Q: In a deck of cards what is the ratio of 2's to 10's?
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Related questions

how ,any 2s are in a deck of cards?

There are four 2s in a deck of cards, one of each suit.


How many 2's are in a deck of cards?

There are four 2s in a deck of cards.


How many 2 cards are in a deck of 52 cards?

There are four 2s in a standard deck of playing cards.


How many 2's are in a deck of 52 cards?

There are four 2s in a standard deck of playing cards.


How many 2's are in a deck of 52?

There are four 2s in a standard deck of playing cards.


How many cards in a Russian card deck?

36 playing cards in a Russian deck. Russian deck starts with 6s. There are same four suits as American deck but 2s, 3s, 4s and 5s are missing.


What size speakers are in a 1987 gmc suburban?

two 4 1/2s and two 4*10s.


Factor the poynomial twice first use a common factor with a positive coefficient and then use a common factor with a negative coefficient -2s4 4s3-10s?

2s(-s^3 + 2s^2 - 5) -2s(s^3 - 2s^2 + 5)


What is 3s plus 4t plus 2s plus 5s plus 6t equals?

3s + 4t + 2s + 5s + 6tGroup all of the like 's' terms & 't' terms together:(3s+2s+5s) + (4t + 6t)10s + 10t or 10(s+t)


Why is it easier to count by 5s or 10s and 2s instead of counting by 3s or 4s?

It is only because we count in tens - and 5 10 and 2 are factors.


If you want to make your own deck of cards--how many 1s are there supposed to be in a deck of cards how many 2s are there supposed to be and so on?

In a traditional deck of cards, there are four of everything. Aces are the ones, so four Aces (Ace of Spades, Ace of Diamonds, Ace of Clubs, Ace of Hearts), four of each number between 2-10 (same suits), and four each of Jacks, Queens, and Kings. There are also two Jokers in a deck, although they are only used for certain games, and removed for others. Of course, if you are making your own, you can change the suits and change the royalty to types of ... cookies, or whatever, but that is what is in a traditional deck, so if you have the same amount of cards, you'll be able to play the same games.


How do you determine the equation for the perpendicular bisector of the straight line joining the points s 2s and 3s 8s?

A = (s, 2s), B = (3s, 8s) The midpoint of AB is C = [(s + 3s)/2, (2s + 8s)/2] = [4s/2, 10s/2] = (2s, 5s) Gradient of AB = (8s - 2s)/(3s - s) = 6s/2s = 3 Gradient of perpendicular to AB = -1/(slope AB) = -1/3 Now, line through C = (2s, 5s) with gradient -1/3 is y - 5s = -1/3*(x - 2s) = 1/3*(2s - x) or 3y - 15s = 2s - x or x + 3y = 17s