Well, if there are twice as many boys as girls in a group of 120 children, that means there are 80 boys and 40 girls. So, there are 40 girls in the group. Math doesn't lie, honey.
Let the number of girls be ( x ). Since there are three times as many boys as girls, the number of boys is ( 3x ). Together, the total number of children is ( x + 3x = 4x ). Setting this equal to 80 gives us ( 4x = 80 ), so ( x = 20 ). Therefore, there are 20 girls in the group.
There are 6 girls and 24 boys. Algebraic solution: Let G = number of girls, B= number of boys G+B = 30 B = 4G Substitute to form G + 4G = 30 5G = 30 G = 6 B = 4G = 4 x 6 = 24
let boys = B and girls = GB +G =120;2G = B;3G = 120;G = 40 and B = 80
If the ratio of boys to girls is 3:7, this means that for every 3 boys, there are 7 girls. To find out how many boys there are, you would need to divide the total number of children by the sum of the parts in the ratio (3 + 7 = 10) and then multiply that result by the number of boys' parts in the ratio (3). So, if there are 30 children in total, there would be 9 boys (30 divided by 10, times 3).
Well, if there are twice as many boys as girls in a group of 120 children, that means there are 80 boys and 40 girls. So, there are 40 girls in the group. Math doesn't lie, honey.
51 girls, 29 boys
Let the number of girls be ( x ). Since there are three times as many boys as girls, the number of boys is ( 3x ). Together, the total number of children is ( x + 3x = 4x ). Setting this equal to 80 gives us ( 4x = 80 ), so ( x = 20 ). Therefore, there are 20 girls in the group.
This means that for every girl there are two boys - so in a group of three, two will be boys and one a girl 45 ÷ 3 = 15 So, there are 15 girls and 30 boys.
There are 40 girls.
C = childrenB = boysG = girlsB = 3G3G + G = C4G = 60G = 15B = 45
The names of the [boys][children] Niños means boys but it could mean a group of children composed of both boys and girls. Niñas means girls.
This means that for every girl there are two boys - so in a group of three, two will be boys and one a girl 45 ÷ 3 = 15 So, there are 15 girls and 30 boys
There are 6 girls and 24 boys. Algebraic solution: Let G = number of girls, B= number of boys G+B = 30 B = 4G Substitute to form G + 4G = 30 5G = 30 G = 6 B = 4G = 4 x 6 = 24
90
72 girls and 18 boys for a total of 90.
Let the number of girls be represented by x. Since there are twice as many boys as girls, the number of boys would be 2x. Therefore, the total number of children is x (girls) + 2x (boys) = 60. This simplifies to 3x = 60. Solving for x, we get x = 20. So, there are 20 girls in the group of 60 children.