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It seems like your question got cut off. However, if you're referring to an equilibrium constant (K) of 1 x 10, this suggests that the concentrations of products and reactants are equal, indicating a balanced reaction. An equilibrium constant of this magnitude generally implies that neither the reactants nor the products are favored significantly, leading to a dynamic equilibrium where both forward and reverse reactions occur at the same rate. If you can provide more specifics or clarify your question, I'd be happy to help further!
What else can I help you with?
What are the values of x y and k when the line y equals 3x plus 1 is a tangent to the circle x squared plus y squared equals k?
If y = 3x + 1 is a tangent to x² + y² = k (k > 0 since it is a square), then where they meet has a repeated root; they meet at: x² + (3x + 1)² = k → x² + 9x² + 6x + 1 - k = 0 → 10x² + 6x + (1 - k) = 0 This is the point of contact when it has a repeated root which is when the discriminant is zero, ie when: 6² + 4 × 10 × (1 - k) = 0 → 36 + 40 - 40k = 0 → 40k = 4 → k = 1/10 I guess for x & y you mean the point where y = 3x + 1 is a tangent to x² + y² = k, ie the point of contact. The value of k can now be substituted into the equation of the point of contact: 10x² + 6x + (1 - k) = 0 → 10x² + 6x + (1 - 1/10) = 0 → 10x² + 6x + 9/10 = 0 → x² + 6x/10 + 9/100 = 0 → (x + 3/10)² → The point of contact is when x = -3/10 → y = 3× -3/10 + 1 = 9/10 + 1 = 1/10 → point of contact is (-3/10, 1/10) with k = 1/10
What is the value of k when the curve x squared plus y squared equals k touches the line y equals 3x plus 1 at just one point?
If: x^2 +y^2 = k then y^2 = k-x^2 If: y = 3x +1 then y^2 = (3x +1)^2 => y^2 = 9x^2 +6x +1 So: 9x^2 +6x +1 = k -x^2 Transposing terms: 10x^2 +6x +(1 -k) = 0 Using the discriminant b^2 -4ab = 0: 36 -4*10*(1 -k)= 0 => -k = -1/10 Therefore: k = 1/10
What is the value of k when the line y equals 3x plus 1 is a tangent to the curve of y2 plus x2 equals k?
If: y = 3x +1 then y^2 = 9x^2 +6x +1 If: y^2 +x^2 = k then y^2 = k -x^2 So: 9x^2 +6x +1 = k -x^2 Transposing terms: 10x^2 +6x +(1 -k) = 0 Using the discriminant: 6^2 -4*10*(1 -k) = 0 Solving the discriminant: k = 1/10
What is the greatest digit number that is divisible by 4?
There is no limit to the number of digits.If, for example, a X is a k-digit number which is divisible by 4 then 10*X is divisible by 4 and 10*X will be a (k+1)-digit number.
What value of k makes the line x equals 7 the perpendicular bisector of the segment with endpoints A 10 2 and B k 2?
As there is no change in y, the perpendicular bisector is given by x = (10 + k)/2 This is given as x = 7; thus: → (10 + k)/2 = 7 → 10 + k = 14 → k = 4
In an equilibruim with a Keq of 1 X 10 8 the?
products are favored
What are the values of x y and k when the line y equals 3x plus 1 is a tangent to the circle x squared plus y squared equals k?
If y = 3x + 1 is a tangent to x² + y² = k (k > 0 since it is a square), then where they meet has a repeated root; they meet at: x² + (3x + 1)² = k → x² + 9x² + 6x + 1 - k = 0 → 10x² + 6x + (1 - k) = 0 This is the point of contact when it has a repeated root which is when the discriminant is zero, ie when: 6² + 4 × 10 × (1 - k) = 0 → 36 + 40 - 40k = 0 → 40k = 4 → k = 1/10 I guess for x & y you mean the point where y = 3x + 1 is a tangent to x² + y² = k, ie the point of contact. The value of k can now be substituted into the equation of the point of contact: 10x² + 6x + (1 - k) = 0 → 10x² + 6x + (1 - 1/10) = 0 → 10x² + 6x + 9/10 = 0 → x² + 6x/10 + 9/100 = 0 → (x + 3/10)² → The point of contact is when x = -3/10 → y = 3× -3/10 + 1 = 9/10 + 1 = 1/10 → point of contact is (-3/10, 1/10) with k = 1/10
What is the hydronium ion concentration of a solution at 298 K whose hydroxide ion concentration is 1 x 10-8 A 1 x 10-6 B 1 x 10-7 C 1 x 10-8 x D 1 x 10-14?
The answer is A 1 x 10^(-6)
What is the value of k when the curve x squared plus y squared equals k touches the line y equals 3x plus 1 at just one point?
If: x^2 +y^2 = k then y^2 = k-x^2 If: y = 3x +1 then y^2 = (3x +1)^2 => y^2 = 9x^2 +6x +1 So: 9x^2 +6x +1 = k -x^2 Transposing terms: 10x^2 +6x +(1 -k) = 0 Using the discriminant b^2 -4ab = 0: 36 -4*10*(1 -k)= 0 => -k = -1/10 Therefore: k = 1/10
What are the values of the variables when the line y equals 3x plus 1 is a tangent to the curve x2 plus y2 equals k?
Equations: y = 3x +1 and x^2 +y^2 = k If: y = 3x +1 then y^2 = 9x^2 +6x +1 If: x^2 +y^2 = k then y^2 = k -x^2 Transposing terms: 10x^2 +6x +(1 -k) = 0 Using the discriminant formula: k = 1/10 Using the quadratic equation formula: x = -3/10 By substitution: y = 1/10
What is the numerical value of Kw at 298 k?
The value of Kw (ion product of water) at 298 K is approximately 1.00 x 10^-14.
What is the value of k when the line y equals 3x plus 1 is a tangent to the curve of y2 plus x2 equals k?
If: y = 3x +1 then y^2 = 9x^2 +6x +1 If: y^2 +x^2 = k then y^2 = k -x^2 So: 9x^2 +6x +1 = k -x^2 Transposing terms: 10x^2 +6x +(1 -k) = 0 Using the discriminant: 6^2 -4*10*(1 -k) = 0 Solving the discriminant: k = 1/10
What is the greatest digit number that is divisible by 4?
There is no limit to the number of digits.If, for example, a X is a k-digit number which is divisible by 4 then 10*X is divisible by 4 and 10*X will be a (k+1)-digit number.
How many atoms are in 0.0671 mol K?
1 mole K = 6.022 x 1023 atoms KConvert known moles to atoms.0.0671mol K X (6.022 x 1023 atoms K/1mol K) = 4.04 x 1022 atoms K
What is the value of k when the line of y equals 3x plus 1 is a tangent to x2 plus y2 equals k?
If: y = 3x +1 then y^2 = 9x^ +6x +1 If: x^2 +y^2 = k then 10^x^2 +6x +(1-k) = 0 Using the discriminant: -4 +40k = 0 Add 4 to both sides: 40k = 4 Divide both sides by 40: k = 1/10 Therefore the value of k is 1/10
What is the integral of 10x?
∫ 10x dx Factor out the constant: 10 ∫ x dx Therefore, by the power rule, we obtain: 10x(1 + 1)/(1 + 1) + k = 10x²/2 + k = 5x² + k
What k -k equals 2?
k and -k right? -k x -1 =k k+k= 2 k= 1 unless you mean multiply then that would be -k x-1 =k k x k= 2 1.4142 rounded to the nearest ten thousandth
