If: x^2 +y^2 = k then y^2 = k-x^2
If: y = 3x +1 then y^2 = (3x +1)^2 => y^2 = 9x^2 +6x +1
So: 9x^2 +6x +1 = k -x^2
Transposing terms: 10x^2 +6x +(1 -k) = 0
Using the discriminant b^2 -4ab = 0: 36 -4*10*(1 -k)= 0 => -k = -1/10
Therefore: k = 1/10
A tangent is a line that just touches a curve at a single point and its gradient equals the rate of change of the curve at that point.
If you mean a line of y = 2x+5/4 and a curve of y^2 = 10x Then it works out that the line touches the curve at: (5/8, 5/2)
Combine the equations together and using the quadratic equation formula it works out that the point of contact is at (5/8, 5/2)
A tangent is an object, like a line, which touches a curve. The tangent only touches the curve at one point. That point is called the point of tangency. The tangent does not intersect (pass through) the curve.
It is a straight line that touches the curve such that the line is perpendicular to the radius of the curve at the point of contact.
A tangent is a line that just touches a curve at a single point and its gradient equals the rate of change of the curve at that point.
If you mean a line of y = 2x+5/4 and a curve of y^2 = 10x Then it works out that the line touches the curve at: (5/8, 5/2)
(2, -2)
Combine the equations together and using the quadratic equation formula it works out that the point of contact is at (5/8, 5/2)
It is (-0.3, 0.1)
If y = 2x +10 and y^2 = 10x then by forming a single quadratic equation and solving it the point of contact is made at (5/8, 5/2)
-2
It is the point at which a tangent touches a curve.
A tangent is an object, like a line, which touches a curve. The tangent only touches the curve at one point. That point is called the point of tangency. The tangent does not intersect (pass through) the curve.
It is a straight line that touches the curve such that the line is perpendicular to the radius of the curve at the point of contact.
-2
If: y = x^2 -10x +13 and y = x^2 -4x +7 Then: x^2 -10x +13 = x^2 -4x +7 Transposing terms: -6x +6 = 0 => -6x = -6 => x = 1 Substituting the value of x into the original equations point of contact is at: (1, 4)