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What is the ratio of Xe and F2 in XeF2?
The ratio of Xe and F2 is 1:1
What fraction is closest to 0.0032677165354331?
There are no "closest" fraction because rational numbers are infinitely dense. If for example, you thought that f1 was the closest fraction, then f2 = 0.5*(f1 + 0.0032677165354331) would be closer. And then f3 = 0.5*(f2 + 0.0032677165354331) would be closer still, and so on.
How will you factor quadratic trynomial?
If the leading coefficient is 1 (or you don't see any number in front of x^2) then find 2 factors f1,f2 which multiply to get the constant term, c, and add to get the coefficient of x, or b,. Then the factors would be (x+f1)(x+f2). Always watch for negatives. Example: x^2 + 2x - 8 B= 2 C= -8 We want 2 numbers that multiply to -8 and add to 2. Since they multiply to a negative number, one must be positive and one must be negative. Since the sum is positive, the larger must also be positive. Analyzing signs can help with determining the factors. With our example, the factors would be 4, -2 so the factor of x^2 + 2x - 8 is (x + 4)(x - 2) To factor quadratic trinomials with a coefficient of the quadratic term , other than 1, I would try the AC method. Here is an example Factor 2x^2 - 3x - 2 With the AC method, find the product of the a, the coefficient of the quadratic term, and c, the constant Here AC = 2*-2 = -4 Then find your b, or coefficient of x B = -3 AC = -4 B = -3 To factor, you need to find a pair of factors that multiply to get AC but adds up to B Our factors would be -4 and 1 since -4*1 = -4 and -4 + 1 = -3 Then rewrite your factors (Ax + f1)(Ax + f2) where f1, f2 are the factors you just found. For our example, (2x - 4)(2x + 1). Finally, factor out any common factor from each binomial (here we can factor 2 out of 2x-4 to get (x - 2)(2x +1)) If this doesn't work, resort to the Quadratic Formula. The factors are then (x - (-b + sqrt(b^2-4ac))/2a)(x - (-b - sqrt(b^2 - 4ac))/2a)
What is the molecular shape of F2?
Linear
What is the molecular geometry of the F2 molecule?
Linear
