In the reaction 2Na + F2 → 2NaF, sodium (Na) is in the solid phase, while fluorine (F2) is in the gaseous phase. The product, sodium fluoride (NaF), is formed as a solid. Thus, the phases for the reactants and products are: 2Na(s) + F2(g) → 2NaF(s).
This is usually called a "displacement" reaction; a metal higher in the electromotive series is displacing a metal below it in the electromotive series in a compound of the latter.
single replacment
2NaH2 + O2 yields 2Na + 2H2O
H2. Hydrogen gas.
koh + h2so4-khso4 +h2o
No.for a start you have potassium on one side (K) and sodium on the other (Na) and what has happened to the Oxygen (O).Your chemical equation does not make any sense.
The chemical equation is:MgF2 + 2 Na = 2 NaF
It is a REDOX reaction. Sodium is oxidized by Fluorine which is itself reduced by the sodium. 2Na + F2 = 2NaF.
NO!!!! There are two fluorines (F2), but only one fluorine in ' NaF '. You have 'lost' a fluorine. Remember the Law of Conservation of Mass. In chemical eq'ns you cannot 'magic' something up out of nowhere, or just lose it. It has to be balanced. Mass has to preserved on both sides of the reaction eq'n. So to balance the eq;n. we need two atom of sodium . Hence 2Na(s) + F2(g) = 2NaF(s) =[ Na-F + Na-F ]. NB Sodium exists as separate atoms hence ' Na + Na = 2Na'. However, fluorine is a diatomic molecule and exists as ' F-F- = 'F2'.
This is usually called a "displacement" reaction; a metal higher in the electromotive series is displacing a metal below it in the electromotive series in a compound of the latter.
single replacment
2NaH2 + O2 yields 2Na + 2H2O
It is an eothermic type of reaction.
To determine the number of atoms in 2NaF, we first need to break down the formula. "2Na" indicates 2 atoms of sodium, while "F" represents 1 atom of fluorine. Therefore, 2NaF contains a total of 3 atoms: 2 atoms of sodium and 1 atom of fluorine.
2 or more
2NH3 + 2NA = 3H2 + NA3N2
Sodium chloride dissolved in water form a solution.