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(n/(18*6))/n4=(n/108)/n4 ;Multiply 18 and 6(n/108)*(1/n4) ;Multiply by the reciprocal of n4, which is just 1 over n4n/(n4*108) ;The n4 will go in the bottom of the fraction1/(108n3) ;n over n4 will give you 1 over n3
4n or n4
The product of four and a number would be algebraically written as 4n, or whatever variable equals the number. In this case, n = number. It would not be written n4, nx4, 4xn, 4*n or n*4, although n4 and the ones with stars may be accepted by a teacher.
1.What is the formula for a proportionp = n / f2. p = (f / 100) * n3. p = f / n4. p = (f / n) * 100
Suppose the smallest of the integers is n. Then the product of the four consecutive integers is n*(n+1)*(n+2)*(n+3) =(n2+3n)(n2+3n+2) = n4+6n3+11n2+6n So product +1 = n4+6n3+11n2+6n+1 which can be factorised as follows: n4+3n3+n2 +3n3+9n2+3n + n2+3n+1 =[n2+3n+1]2 Thus, one more that the product of four consecutive integers is a perfect square.