numbers that are divisible by 4 is either: 4n or numbers in which the number formed by last two digits are divisible by 4
Assuming you mean 4 consecutive whole numbers, the answer is number that can be expressed as 4n+10 where n is an integer.
4, 8, 12
Homework question: The first numbetr is 4. A rule is multiply by 2 and then subtract 3. What are the first 6 numbers in the pattern
4n+13=1 -13 -134n=-12/4 /4n=-3
numbers that are divisible by 4 is either: 4n or numbers in which the number formed by last two digits are divisible by 4
4 + 4n - 12 = 4n - 8
the first 4 terms of the sequence which has the nth term is a sequence of numbers that that goe together eg. 8,12,16,20,24 the nth term would be 4n+4
Assuming you mean 4 consecutive whole numbers, the answer is number that can be expressed as 4n+10 where n is an integer.
To find the equation of a sequence, you first have to look at the differences between the numbers. In this case the differences are 4, and 4. Thus the equation begins 4n. The sequence minus 4n is: 3, 3, 3 Thus the equation in its entirety is that the value of the term in position n is 4n+3
4, 8, 12
well first u dont spell common coomon
n = 1 7n + 6n - 5 = 4n + 4 13n - 5 = 4n + 4 13n - 4n - 5 = 4n - 4n + 4 9n - 5 = 4 9n -5 + 5 = 4 + 5 9n = 9 n = 1
4n + 3 = 15 4n +3 - 3 = 15 - 3 4n = 12 4n/4 = 12/4 n = 3
4n = 48 4n/4 = 48/4 (Divide by 4 on both sides and then cancel) n = 12
Homework question: The first numbetr is 4. A rule is multiply by 2 and then subtract 3. What are the first 6 numbers in the pattern
Well, honey, the first five terms for the sequence 4n + 7 are 11, 15, 19, 23, and 27. Just plug in n = 1, 2, 3, 4, 5 and you'll get those numbers. Math can be a piece of cake if you just follow the recipe!