342 of them.
Eleven digit numbers are those in the range between 9,999,999,999 and 100,000,000,000 exclusive. There are 90,000,000,000 of these.
To find how many times the digit 3 occurs in the hundreds place for numbers between 100 and 10,000, we consider all three-digit and four-digit numbers. The hundreds place can be 3 in the range from 300 to 399, which gives us 100 occurrences (300 to 399 inclusive). For four-digit numbers, the hundreds place can also be 3, covering the range from 3,000 to 3,999, which again totals 1,000 occurrences. Therefore, the digit 3 occurs 1,100 times in the hundreds place from 100 to 10,000.
10001
There are 90 two-digit numbers possible. The first digit can range from 1 to 9 (9 options), while the second digit can range from 0 to 9 (10 options). Therefore, the total number of two-digit numbers is 9 (first digit) multiplied by 10 (second digit), which equals 90.
Three-digit numbers range from 100 to 999. To find the count of three-digit numbers between 99 and 3000, we consider the range from 100 to 999, which includes 900 numbers (999 - 100 + 1 = 900). Thus, there are 900 three-digit numbers between 99 and 3000.
14
There are 11520 of them.
In base ten, there are 9000 four digit number, the numbers are from 1000 to 9999. If you allow leading zeros, then there are 10000 numbers. [0000 - 9999]
90000. With 10 digit palindromes, the last 5 digits are the same as the first 5 digits in reverse, eg 12345 54321. So it comes down to how many 5 digit numbers are there? They are the numbers "10000" to "99999", a total of 99999 - 10000 + 1 = 90000.
Assuming positive integers, and no leading zeros, the range of five digit numbers is 10000 to 99999. The ones that end in zero can be found by taking the four digit numbers: 1000 to 9999 and multiplying each by ten. {1000,1001, 1002, ...9999}, multiplied by ten is {10000,10010,10020,....99990}. There are 9000 of them.
Eleven digit numbers are those in the range between 9,999,999,999 and 100,000,000,000 exclusive. There are 90,000,000,000 of these.
72. (with the range of two digit numbers being from 10 to 99).
To find how many times the digit 3 occurs in the hundreds place for numbers between 100 and 10,000, we consider all three-digit and four-digit numbers. The hundreds place can be 3 in the range from 300 to 399, which gives us 100 occurrences (300 to 399 inclusive). For four-digit numbers, the hundreds place can also be 3, covering the range from 3,000 to 3,999, which again totals 1,000 occurrences. Therefore, the digit 3 occurs 1,100 times in the hundreds place from 100 to 10,000.
10001
There are 90 two-digit numbers possible. The first digit can range from 1 to 9 (9 options), while the second digit can range from 0 to 9 (10 options). Therefore, the total number of two-digit numbers is 9 (first digit) multiplied by 10 (second digit), which equals 90.
Three-digit numbers range from 100 to 999. To find the count of three-digit numbers between 99 and 3000, we consider the range from 100 to 999, which includes 900 numbers (999 - 100 + 1 = 900). Thus, there are 900 three-digit numbers between 99 and 3000.
The smallest one in that range is 1,000. The largest one in that range is 6,000.All the numbers between 1,000 and 6,000 are 4-digit numbers. There are6,000 - 999 = 5,001of them.