Arthur Pythagoras he say AB2 = AC2 + BC2,
so AB2 = 81 + 144 ie AB = sqrt 225 = 15 cm
It's a right angle triangle and its length is 12 units of measurement.
By using Pythagoras; theorem for a right angle triangle.
hypotenuse = sqr ( 5² + 12² ) = 13.
It is: 37 units in length
The other leg length is 16.
The median to the hypotenuse of a right triangle that is 12 inches in length is 6 inches.
The length of the hypotenuse of a right triangle with legs of lengths 5 and 12 units is: 13The length of a hypotenuse of a right triangle with legs with lengths of 5 and 12 is: 13
ABC is an equilateral triangle with side length equal to 50 cm. BH is perpendicular to AC. MN is parallel to AC. Find the area of triangle BMN if the length of MN is equal to 12 cm.
ABC is an equilateral triangle with side length equal to 50 cm. BH is perpendicular to AC. MN is parallel to AC. Find the area of triangle BMN if the length of MN is equal to 12 cm.
It's a right angle triangle and its length is 12 units of measurement.
The length of the hypotenuse of a right triangle that has a base of 3 feet and a height of 12 feet is: 12.37 feet.
If the legs of a right triangle have measures of 9 and 12, the hypotenuse is: 15
9
12
By using Pythagoras; theorem for a right angle triangle.
hypotenuse = sqr ( 5² + 12² ) = 13.
15 in