AB + AC + BC = 48 AB + (AB +9) + (AB + 9 + 3) = 48
Solve and AB = 9
So AB = 9, AC = 18 and BC = 21
The length of each side is longer than the sum of the lengths of the other two sides.
This is merely a doubling of the 5-12-13 triangle. The sides are 10 and 24 ft.
a rectangle as a longer side because there's 48 inches for a rectangle but there's only 45 inches for a triangle. a rectangle as a longer side because there's 48 inches for a rectangle but there's only 45 inches for a triangle.
No.To make a triangle the sum of the two shorter sides mustbe longer than the third. With 3.1, 4.3, 10.9 the two shorter sides are 3.1 and 4.3 which have a length sum of 3.1 + 4.3 = 7.4 which is not longer than 10.9, so 3.1, 4.3 and 10.9 cannot form a triangle.
I am not sure what you mean by a "fundamental" number (I've never heard of that term being used with reference to the numbers themselves); I guess you mean an "integer". For a triangle to exist the shorter two sides must be longer than the longest side. Thus there is an upper limit to the length of the longest side of a triangle. For a given perimeter, the longest side must be less than half the perimeter. For a perimeter of 42cm this means that the longest side is less than 42 cm ÷ 2 = 21 cm. If we focus on the longest side of a triangle, as it becomes shorter, one or both of the other two sides must increase in length, they can equal but never be longer than this longest side. Thus there is also a lower limit below which the longest side cannot be; this is when all three sides are equal and the triangle is an equilateral triangle. For a perimeter of 42cm the longest side is greater than or equal to 42 cm ÷ 3 = 14 cm So with a perimeter of 42 cm we have: 14 cm ≤ longest side < 21 cm Which means for an integer length, the longest side can be 14 cm, 15 cm, 16 cm, 17 cm, 18 cm, 19 cm or 20 cm.
The perimeter is the sum of all of the sides of the triangle. If the shorter leg is x, the longer leg is 3x. The hypotenuse is then the square root of x^2 + 3x^2, or 2x. Then the perimeter is x + 3x + 2x, simplified, f(x) = 6x.
The length of each side is longer than the sum of the lengths of the other two sides.
Length of longer leg = 9.4 tan 60 = 16.28 feet Length of hypotenuse = 9.4 ÷ cos 60 = 18.8 feet Perimeter of triangle = 9.4 + 16.28 + 18.8 = 44.48 feet
No, waves with longer wavelengths have lower frequencies and waves with shorter wavelengths have higher frequencies. Frequency is inversely proportional to wavelength in a wave.
The minimum perimeter is when the triangle is an equilateral triangle. The perimeter of any other triangle with the same area will be longer. In the case of an equilateral triangle area = (√3)/4 × side² → side = √(4×6.5 cm²/√3) → perimeter = 3 × side = 3 × √(4×6.5 cm²/√3) ≈ 11.62 cm → The triangle has a perimeter greater than or equal to approx 11.62 cm.
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Suppose the side of the square is x cm.Then its perimeter is 4x cm.The perimeter of the square is 3 cm more than that of the triangleso the perimeter of the triangle is 4x - 3 cm.Also, if the side of the square is x cm, the side of the triangle must be x + 112 cm.Then its perimeter must be 3*(x + 112) = 3x = 336 cm.Equating the two expressions for the perimeter of the triangle,4x - 3 = 3x + 336therefore x = 339 cm.The square has sides of 339 cm and a perimeter of 1356 cm.The triangle has sides of 451 cm and a perimeter of 1353 cm.
This is merely a doubling of the 5-12-13 triangle. The sides are 10 and 24 ft.
An isosceles triangle. It is an isosceles triangle even if the third side is shorter.
Let x be the side of the triangle. Thus 4(x-5) is the perimeter of the square.Balance by the perimeter relation,3x = 7+4(x-5)Solve for x,x = 13 inches
shorter side = 10 longer side = 19
For a triangle to exist, the sum of the shorter two sides must be longer than the third side.