shorter side = 10 longer side = 19
40 meters.
Area of a rectangle is width times lenght. 14m in lenght (times) 5m in width = 70m2
Since the formula for the perimeter of a rectangle is 2 times the lenght plus 2 times the width (P = 2l + 2w). P = 2(8) + 2(3) P = 16 + 6 P = 22m
To find the width of a rectangle, multiply the lenght by 2 and subtract it from the perimeter. Once this is done you are left with the two width sides of the rectangle. To find the width divide this number by 2 and you have your answer. For exaple: P= 120 cm L= 40 cm L* 2 = 80 120 - 80 = 40 40/2 = 20 W=20
to find the perimeter you must add all sides. and to find area you have to multiply lenght and width
a rectangle had a perimeter of 48 and the longest side is 15 find the lenght of a shorter side
You divide the perimeter by the width and you get the lenght
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the perimeter of a rectangle is 700 yards. what are the dimensions of the rectangle if the lenght is 80 yards more than the width?
40 meters.
Just add the four sides.
The perimeter of a rectangle is 2L + 2W. L will be used for lenght. Since the width is 6 inches less than the lenght, width can be defined as L-6. So you use substution. 2(L) + 2(L-6) = 52 2L + 2L -12 = 52 4L = 64 L = 16 Since L = 16 and the width is L-6 --->16-6 = 10 for your width.
24m x 34m
Because the perimeter is lenght + length +width +width, you do perimeter - double the width, and then halve the remaining number. that should give you the length.
The length is 16 and the width is 4. 2x16 plus 2x4 equals 40.
the width of the rectangle is 12.....because area= lenght x width so if the lenght is 5 inches and the area is 60....u divide 60 divided by 5 = 12
The length of the shorter side is 16cm The formula for the perimeter of a rectangle is p = 2a + 2b, p = 100cm, a = 34cm 2b = p - 2a = 100 - 68 = 32 b = 16cm