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How do you create an equation for a parabola?
An equation for a parabola always has some type of irregular variable, usually a squared variable or higher.
What is the y coordinate of the vertex of the parabola that is given y equals negative 2 point 5 parenthese x minus 4 parenthese end squared minus 5?
y = -5 By using calculus, the derivative of y = -2.5(x-4)2 - 5 is y' = -5(x-4). Solving the equation -5(x-4) = 0 gives x = 4 (since the slope of the parabola at the vertex is zero). Plug this back into the equation: y = -2.5(4 - 4) -5 = -5, so the y-coordinate is -5. The equation of the parabola is given in the vertex form y = a(x - h)2 + k, where (h, k) is the vertex. So the vertex is (4, -5).
What type of equation results in a graph of a parabola?
A parabola looks like a frowning face :( or a smiling face :) The type of equation that would give you a parabola is called a Quadratic equation. Quadratic equations have x^2 as the highest exponent in the equation. ex: x squared + 2x + 1
In which direction will this parabola open y-8(x plus 5)2 plus 2?
The given equation of the parabola is in the vertex form (y - 8 = a(x + 5)^2 + 2). Here, (a) is the coefficient of the squared term. Since the coefficient of ((x + 5)^2) is positive (as it's implied to be 1), the parabola opens upwards. Therefore, the parabola opens in the direction of positive y-values.
How can you tell which way a parabola wil open just by lookig at the equation?
If you have the equation in the form y = ax^2 + bx + c (where "^2" means squared), if "a" is positive, the parabola opens upwards; otherwise it opens downwards.
How do you create an equation for a parabola?
An equation for a parabola always has some type of irregular variable, usually a squared variable or higher.
The vertex of this parabola is at -2 -3 When the y-value is -2 the x-value is -5 What is the coefficient of the squared term in the parabola's equation?
The vertex of this parabola is at -2 -3 When the y-value is -2 the x-value is -5. The coefficient of the squared term in the parabola's equation is -3.
What is Y equals x squared plus 1?
It is the equation of a parabola.
The vertex of this parabola is at 5 5 When the x-value is 6 the y-value is -1 What is the coefficient of the squared expression in the parabola's equation?
The vertex of this parabola is at 5 5 When the x-value is 6 the y-value is -1. The coefficient of the squared expression in the parabola's equation is -6.
What is the equation for a parabola?
The general equation for a parabola is y = ax^2 + bx + c, where a, b, and c are constants that determine the shape, orientation, and position of the parabola.
What is the parabola?
A parabola is a type of graph that is not linear, and mostly curved. A parabola has the "x squared" sign in it's equation. A parabola is not only curved, but all the symmetrical. The symmetrical point, the middle of the parabola is called the vertex. You can graph this graph with the vertex, x-intercepts and a y-intercept. A parabola that has a positive x squared would be a smile parabola, and the one with the negative x squared would be a frown parabola. Also, there are the parabolas that are not up or down, but sideways Those parabolas have x=y squared, instead of y = x squared.
What is the y coordinate of the vertex of the parabola that is given y equals negative 2 point 5 parenthese x minus 4 parenthese end squared minus 5?
y = -5 By using calculus, the derivative of y = -2.5(x-4)2 - 5 is y' = -5(x-4). Solving the equation -5(x-4) = 0 gives x = 4 (since the slope of the parabola at the vertex is zero). Plug this back into the equation: y = -2.5(4 - 4) -5 = -5, so the y-coordinate is -5. The equation of the parabola is given in the vertex form y = a(x - h)2 + k, where (h, k) is the vertex. So the vertex is (4, -5).
What type of equation results in a graph of a parabola?
A parabola looks like a frowning face :( or a smiling face :) The type of equation that would give you a parabola is called a Quadratic equation. Quadratic equations have x^2 as the highest exponent in the equation. ex: x squared + 2x + 1
The vertex of this parabola is at (2, -4) When the y-value is -3, the x-value is -3 What is the coefficient of the squared term in the parabola's equation?
-5
The vertex of this parabola is at 4 -3 When the x-value is 5 the y-value is -6 What is the coefficient of the squared expression in the parabola's equation?
-3
The vertex of this parabola is at (4 -3). When the x-value is 5 the y-value is -6. What is the coefficient of the squared expression in the parabola's equation?
-3
In which direction will this parabola open y-8(x plus 5)2 plus 2?
The given equation of the parabola is in the vertex form (y - 8 = a(x + 5)^2 + 2). Here, (a) is the coefficient of the squared term. Since the coefficient of ((x + 5)^2) is positive (as it's implied to be 1), the parabola opens upwards. Therefore, the parabola opens in the direction of positive y-values.
