The vertex of this parabola is at 5 5 When the x-value is 6 the y-value is -1. The coefficient of the squared expression in the parabola's equation is -6.
you didn't put any equations, but the answer probably begins with y= (x-4)^2+1
A parabola with vertex (h, k) has equation of the form: y = a(x - h)² + k → vertex (k, h) = (3, 5), and a point on it is (-1, 6) → 6 = a(-1 - 3)² + 5 → 6 = a(-4)² + 5 → 1 = 16a → a = 1/16 → The coefficient of the x² term is 1/16
The equations for any conic section (which includes both parabolas and circles) can be written in the following form: Ax^2+Bxy+Cy^2+Dx+Ey+F=0 Some terms might be missing, in which case their coefficient is 0. The way to figure out if the equation is a parabola, circle, ellipse, or hyperbola is to look at the value of B^2-4AC: If it's negative, the graph is an ellipse (of which a circle is a special case). If it's 0, the graph is a parabola. If it's positive, the graph is a hyperbola. The special case of a circle happens when B is 0 -- there is no "xy" term -- and A=C.
How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).
The given equation is not that of a parabola since there are no powers of 2. Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).
A coefficient is a number that accompanies a variable. For example, in the expression 2x + 4, the coefficient is 2.
The vertex of this parabola is at -3 -1 When the y-value is 0 the x-value is 4. The coefficient of the squared term in the parabolas equation is 7
7
It is 1/16.
-3
-3
u look at it.... :-) hey I'm learning about parabolas too
Go study
The vertex of this parabola is at -2 -3 When the y-value is -2 the x-value is -5. The coefficient of the squared term in the parabola's equation is -3.
The vertex of this parabola is at -5 -2 When the x-value is -4 the y-value is 2. The coefficient of the squared expression in the parabola's equation is 4. y = a(x - h)2 + k; (h, k) = (-5, -2); (x, y) = (-4, 2) 2 = a[-4 -(-5)]2 - 2, add 2 to both sides 4 = a(-4 +5)2 4 = a(1)2 4 = a
right
Vertex = (3, - 2)Put in vertex form.(X - 3)2 + 2X2 - 6X + 9 + 2 = 0X2 - 6X + 11 = 0=============The coefficeint of the squared term is 1. My TI-84 confirms the (4, 3) intercept of the parabola and the 11 Y intercept shown by the function.