The vertex of this parabola is at 5 5 When the x-value is 6 the y-value is -1. The coefficient of the squared expression in the parabola's equation is -6.
you didn't put any equations, but the answer probably begins with y= (x-4)^2+1
A parabola with vertex (h, k) has equation of the form: y = a(x - h)² + k → vertex (k, h) = (3, 5), and a point on it is (-1, 6) → 6 = a(-1 - 3)² + 5 → 6 = a(-4)² + 5 → 1 = 16a → a = 1/16 → The coefficient of the x² term is 1/16
The equations for any conic section (which includes both parabolas and circles) can be written in the following form: Ax^2+Bxy+Cy^2+Dx+Ey+F=0 Some terms might be missing, in which case their coefficient is 0. The way to figure out if the equation is a parabola, circle, ellipse, or hyperbola is to look at the value of B^2-4AC: If it's negative, the graph is an ellipse (of which a circle is a special case). If it's 0, the graph is a parabola. If it's positive, the graph is a hyperbola. The special case of a circle happens when B is 0 -- there is no "xy" term -- and A=C.
How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).
The given equation is not that of a parabola since there are no powers of 2. Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).
The coefficient of the squared term in a parabola's equation, typically expressed in the standard form (y = ax^2 + bx + c), is represented by the value (a). This coefficient determines the direction and the width of the parabola: if (a > 0), the parabola opens upwards, and if (a < 0), it opens downwards. The larger the absolute value of (a), the narrower the parabola.
A coefficient is a number that accompanies a variable. For example, in the expression 2x + 4, the coefficient is 2.
The vertex of this parabola is at -3 -1 When the y-value is 0 the x-value is 4. The coefficient of the squared term in the parabolas equation is 7
7
It is 1/16.
To find the coefficient of the squared expression in the parabola's equation, we can use the vertex form of a parabola, which is ( y = a(x - h)^2 + k ), where ((h, k)) is the vertex. Given the vertex is ((-4, -1)), the equation becomes ( y = a(x + 4)^2 - 1 ). When (y = 0) and (x = 2), substituting these values gives (0 = a(2 + 4)^2 - 1), leading to (0 = a(6^2) - 1) or (1 = 36a). Therefore, (a = \frac{1}{36}), which is the coefficient of the squared expression.
-3
-3
u look at it.... :-) hey I'm learning about parabolas too
To find the coefficient of the squared term in the parabola's equation, we can use the vertex form of a parabola, which is (y = a(x - h)^2 + k), where ((h, k)) is the vertex. Given the vertex at (3, 1), the equation starts as (y = a(x - 3)^2 + 1). Since the parabola passes through the point (4, 0), we can substitute these values into the equation: (0 = a(4 - 3)^2 + 1), resulting in (0 = a(1) + 1). Solving for (a), we find (a = -1). Thus, the coefficient of the squared term is (-1).
The vertex of this parabola is at -2 -3 When the y-value is -2 the x-value is -5. The coefficient of the squared term in the parabola's equation is -3.
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