A number, t, is a triangular number if (1 + 8t) is a square of an odd number.
multiply by some number, whatever number you wand\t or need.
Count the number of elements in the set - call this number n. Add up all the numbers in the set - call this total t Then mean = t/n
The lower bound of a set S if a number L such that L < s for all s in S and, given another number d (however small), there is an element t, in S such that t < L+d.
t-j. Happy Christmas!
#include<stdio.h> #include<conio.h> void main() { int s,c,p,n,i,t; printf("Enter a number:"); scanf("%d",&n); s=n*n; c=0; p=1; t=n; while(n!=0) { c++; n=n/10; } for(i=1;i<=c;i++) p=p*10; if(s%p==t) printf("The number is automorphic."); else printf("Not automorphic."); getch(); }
printf(\n "ENTER THE NUMBER\t"); scanf{"%d",&a); while(a!=0); { r=a%2; if(r==0) printf("\n\n THE NUMBER IS EVEN \t"); else printf("\n\n THE NUMBER IS ODD \t"); printf ("\n ENTER THE NUMBER \t"); scanf("%d",&a); } getch(); }
One can find my wireless number on my at and t hotspot by going to manage my internet account.
No it will not
a=input("Enter your customer call number\t:") print("***********************************************************************************************************************************************************************") print("\t\t\t\t\t\t\t\t\tWELCOME TO OUR COUSTOMER CARE") def cust(): print("***********************************************************************************************************************************************************************") print("\nPlease choose your language options\t:\n***********************************************************************************************************************************************************************\n\t\t\t\t\t\t\t\tPlease choose your language options:\n\t\t\t\t\t\t\t\t\t:-Press 1 for Telugu\n\t\t\t\t\t\t\t\t\t:-Press 2 for English\n\t\t\t\t\t\t\t\t\t:-Press 3 for Hindi\n\t\t\t\t\t\t\t\t\t:-Press 4 for exit\n***********************************************************************************************************************************************************************") b=input("Please choose your language\t:") def menu(): if(b==1): print ("\n************************************************************************************************************************************************************************\n\t\t\t\t\t\t\t:-Press 1 for balance enquiring\n\t\t\t\t\t\t\t:-Press 2 for recharge\n\t\t\t\t\t\t\t:-Press 3 for dailer tunes\n\t\t\t\t\t\t\t:-Press 4 for to know your cell details\n\t\t\t\t\t\t\t:-Press 0 for go to previous menu\n************************************************************************************************************************************************************************") c=input("Please Enter your option\t:") if(c==1): a=input("Please enter the balance enquiry number\t:") print"\nYour balance is 35.59 Rupees\nThank you." d=input("Do You want Main menu again press Other Wise U will Exit:\t"); if(d==-1): return menu(); elif(c==2): print("\n**********************************************************************************************************************************************************************\n\t\t\t\t\t\t\t:-Press 1 for your own accout\n\t\t\t\t\t\t\t:-Press 2 for any other account\n************************************************************************************************************************************************************************") d=input("Please enter your option\t:") if(d==1): print"\nEnter *123* and then enter your voucher numeber and finally press # and dail.\nMessage:-Successfully recharge:\t" d=input("Do You want Main menu again press -1 Other Wise U will Exit:\t"); if(d==-1): return menu(); elif(d==2): e=input("Please Enter the phone number\t:") f=input("How much of amount you recharge\t:") f=open("customer.txt","a") f.write("\n") f.write("your given amount Successfully recharged.") f.close() print "\nSuccess fully recharged." d=input("Do You want Main menu again press -1 Other Wise U will Exit:\t"); if(d==-1): return menu(); else: print "Please give correct option." d=input("Do You want Main menu again press -1 Other Wise U will Exit:\t"); if(d==-1): return menu(); elif(c==3): print("\n:-Press 1 for New songs\n:-Press 2 for old songs\n:-Press 3 for classical songs\t:") g=input("Please Enter your option\t:") if(g==1): new=raw_input("Enter which new song you want\t:") print new,"tone is selected to your mobile.\nThank you" d=input("Do You want Main menu again press -1 Other Wise U will Exit:\t"); if(d==-1): return menu(); elif(g==2): old=raw_input("Enter which old song you want\t:") print old,"tone is selected to your mobile.\nThank you" d=input("Do You want Main menu again press -1 Other Wise U will Exit:\t"); if(d==-1): return menu(); elif(g==3): cla=raw_input("Enter which classical song you want\t:") print cla,"tone is selected to your mobile.\nThank you" d=input("Do You want Main menu again press -1 Other Wise U will Exit:\t"); if(d==-1): return menu(); else: print"Please choose correct option" d=input("Do You want Main menu again press -1 Other Wise U will Exit:\t"); if(d==-1): return menu(); elif(c==4): h=input("Please tell your mobile number\t:") print"Your mobile number details\t:::\n\tName:RajaMohan\n\tAddress:Door N0. 2-13, peddaveedhim Penturu,Nandigam (mdl & po)\n\tDistrict:Srikakulam" d=input("Do You want Main menu again press -1 Other Wise U will Exit:\t"); if(d==-1): return menu(); menu() cust(); #BY RajaMoahn @RGUKT Nuzvid 2010
You find a multiple of a number by multiplying that number by any whole number.
A number, t, is a triangular number if (1 + 8t) is a square of an odd number.
The quotient of T times 12. You will have to find the value of the letter T.
It means that if you multiply 't' by any number, 'x' becomes multiplied by the same number. If you double 't', you'll find that 'x' has also doubled. If you reduce 't' by 72.6 percent, you'll find that 'x' has also shrunk by 72.6 percent.
multiply by some number, whatever number you wand\t or need.
you text to 150
input