0
Take any valid 4 x 4 magic square. For example:
9 6 3 16
4 15 10 5
14 1 8 11
7 1 10 16
Decrease every number by 6, so that the smallest number you will find in the square is -5, and the largest number in the square will be 10. This is a valid magic square for the set of numbers given and can be rotated any of four ways, and reflected either of two ways.
Still curious? Ask our experts.
Chat with our AI personalities
Beau
Rene
JudyAdd your answer:
Earn +20 pts
Square root of 25 is integer?
Well, the square root of 25 is five, and 5 is an integer, yes.
Why cant 10 to the power of 50 3 be a square number?
10 = 2*5 (prime decomposition)So for a power of 10 to be a square means that the powers its factors must be even. A power of 10 is a square if it contains an even number of factors of 2 and 5. Since 503 is an odd number, 10^503 has an odd number of powers of 2 and 5, so it can't be the square of an integer.
Is -10 divided by 2 an integer?
-12
Is the square root of negative 5 an integer?
No, it is not even a real number. The square root of negative 5 is the square root of 5, times i.
Does the number 5 always have to be in the middle of a magic square?
Think! What if the magic square had an even number of cells. There's your answer.
