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This can easily be integrated by substitution.

Integrate[(6x3+8)418x2 dx]

let u=(6x3+8)

du/dx= 18x2

du=18x2 dx

Substituting u in gives...

Integrate [u4 du] = (1/5)(u5) + C

Substituting x back in gives..

(1/5)(6x3+8)5 + C

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15y ago

What else can I help you with?