since 2 to the third power(2x2x2)=8
Then two to the third power times two to the third power
(8x8) = 64
2x2x2 = 8
2 to the third power x 17 to the 7th power = 3,282,709,384
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(-2)^3 equals -2 times -2 times -2 which equals -8
(-2)(2^3) = (-2)(8) = (-16)
no it would be A to the fourth power
512
If you mean: 2^3 times 2^7 times 2^3 then it equals 8192
2^(6) X 2^(3) = 2^(6+3) = 2^(9) = 512 NB Providing the coefficients is the same, '2' in this case, when multiplying you just add the indices/power/exponentials. Similarly For division , subtract the indices. 2^(6) divide 2^(3) = 2^(6-3) = 2^(3) = 8 For 'nesting' , multiply the indices. [2^(6)]^(3) = 2^(6x3) = 2^(18) = 262144 NB In all cases the coefficient MUST be the same. NNB Something along the lines of 2^(3) X 3^(2) does NOT work by adding/subtracting/nesting the indices. , because the coefficients are different.
2 to the third power x 17 to the 7th power = 3,282,709,384
2 to the third power times 5 to the fifth power equals 25,000
2,000
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2*103 = 2000
2 to the 3rd power equals 8, because 2 times 2 times 2 equals 8.
27. 1 times 2 is just 2. 3 to the third power is 3 times 3 which is 9, times 3, which is 27. If you multiply that by 1 again, it's STILL 27.
(-2)^3 equals -2 times -2 times -2 which equals -8
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