Exterior angle = 360/20=18
interior angle = 180 - 18 = 162
Must be regular shape
For an 18-sided polygon (octadecagon), the formula to calculate the interior angle is ((n-2) \times 180° / n), where (n) is the number of sides. Substituting (n = 18), the interior angle is ((18-2) \times 180° / 18 = 160°). The exterior angle can be found using the formula (360° / n), which gives (360° / 18 = 20°). Therefore, each interior angle is 160° and each exterior angle is 20°.
The exterior angle of a regular polygon can be calculated using the formula ( \frac{360^\circ}{n} ), where ( n ) is the number of sides. For a regular 20-sided shape (icosagon), the exterior angle is ( \frac{360^\circ}{20} = 18^\circ ). Therefore, each exterior angle of a regular 20-sided shape measures 18 degrees.
If it's regular then 360/20 = 18 degrees
162o. Method 1: Sum of interior angles of n-sided polygon = (2n - 4) right angles. In this case n = 20 so total of interior angles is 36 x 90o. Assuming polygon is regular then each interior angle is (36 x 90) divided by 20 = 3240/20 = 162. Method 2: Exterior angles of regular n-sided polygon = 360/n which in this case = 360/20 =18. Straight line is 180o so interior angle = (180 - exterior angle) = 180 - 18 = 162.
Interior angles total 40 - 4 right angles, ie 36 x 90o, so each interior angle is 18 x 9 ie 162o and the exterior is 180 - 162 = 18o
To work out the interior angle use this formula(n - 2)*180/nwhere n is the number of sidesso for an 18 sided shape it would be(18-2)*180/18 = 160.
For an 18-sided polygon (octadecagon), the formula to calculate the interior angle is ((n-2) \times 180° / n), where (n) is the number of sides. Substituting (n = 18), the interior angle is ((18-2) \times 180° / 18 = 160°). The exterior angle can be found using the formula (360° / n), which gives (360° / 18 = 20°). Therefore, each interior angle is 160° and each exterior angle is 20°.
3240
3240
exterior angle = 360° ÷ 20 sides = 18° interior angle = 180° - exterior angle = 180° - 18° = 162°
164o 20' 52.17''
Providing that it is a regular 20 sided icosagon the each interior angle measures 162 degrees
If it's regular then 360/20 = 18 degrees
162o. Method 1: Sum of interior angles of n-sided polygon = (2n - 4) right angles. In this case n = 20 so total of interior angles is 36 x 90o. Assuming polygon is regular then each interior angle is (36 x 90) divided by 20 = 3240/20 = 162. Method 2: Exterior angles of regular n-sided polygon = 360/n which in this case = 360/20 =18. Straight line is 180o so interior angle = (180 - exterior angle) = 180 - 18 = 162.
The exterior angle of a 18 sided shape is 360/18 =20 degrees The exterior angle is always 360 divided by the numbe of sides of that polygon. =) what the hell im i doing answering this?
Interior angles total 40 - 4 right angles, ie 36 x 90o, so each interior angle is 18 x 9 ie 162o and the exterior is 180 - 162 = 18o
In a regular 18-sided polygon, the measure of each interior angle can be calculated using the formula ((n-2) \times \frac{180^\circ}{n}), where (n) is the number of sides. For an 18-sided polygon, each interior angle is ( \frac{(18-2) \times 180^\circ}{18} = 160^\circ). The exterior angle, which is supplementary to the interior angle, measures (180^\circ - 160^\circ = 20^\circ). Thus, each interior angle is 160 degrees, while each exterior angle is 20 degrees.