The exterior angle of a 18 sided shape is 360/18 =20 degrees The exterior angle is always 360 divided by the numbe of sides of that polygon. =) what the hell im i doing answering this?
exterior angle = 360° ÷ 20 sides = 18° interior angle = 180° - exterior angle = 180° - 18° = 162°
All I can tell you is that a 16 sided shape is called a Hexadecagon
Tetrahaidecahedron
If those are exterior angles, the exterior angles of any polygon add up to 360. That would be 18 sides.
Octadecadron
The exterior angle of a regular polygon can be calculated using the formula ( \frac{360^\circ}{n} ), where ( n ) is the number of sides. For a regular 20-sided shape (icosagon), the exterior angle is ( \frac{360^\circ}{20} = 18^\circ ). Therefore, each exterior angle of a regular 20-sided shape measures 18 degrees.
Exterior angle = 360/20=18 interior angle = 180 - 18 = 162 Must be regular shape
If it's regular then 360/20 = 18 degrees
A regular 18 sided polygon has 18 exterior angles each measuring 20 degrees
To work out the interior angle use this formula(n - 2)*180/nwhere n is the number of sidesso for an 18 sided shape it would be(18-2)*180/18 = 160.
18 degrees
For an 18-sided polygon (octadecagon), the formula to calculate the interior angle is ((n-2) \times 180° / n), where (n) is the number of sides. Substituting (n = 18), the interior angle is ((18-2) \times 180° / 18 = 160°). The exterior angle can be found using the formula (360° / n), which gives (360° / 18 = 20°). Therefore, each interior angle is 160° and each exterior angle is 20°.
Each exterior angle will measure 360/18 = 20.0 degrees
56
The exterior angles add up to 360 degrees.
exterior angle = 360° ÷ 20 sides = 18° interior angle = 180° - exterior angle = 180° - 18° = 162°
20 degrees