0
What else can I help you with?
What is the solution of y equals 0 and x equals y plus 2?
y = 0x = y + 2plug 0 in for yx = 0 + 2x = 2
What number of tiles that will make a rectangle that is2 tiles wide?
The answer is 2*k where k is any integer greater than 0.
Use the Substitution method to solve the system of equationsx plus y equals -4 and x - y equals 2?
x + y = -4x - y = 2x - y = 2x + y - y = 2 + yx = 2 + yx + y = -42 + y + y = -42 + 2y = -42 - 2 + 2y = -4 - 22y = -62y/2 = -6/2y = -3x = 2 + yx = 2 - 3x = -1The solution of the system is (-1, -3)
Is 0 2 a solution to y -x plus 2?
Yes, 0, 2 is a solution to y=-x+2 because 0=-2+2 which can be rewritten as 2-2=0.
What is the solution to (0 -4) (0 -2)?
If they are to be multiplied then the solution is 8
What is the solution of y equals 0 and x equals y plus 2?
y = 0x = y + 2plug 0 in for yx = 0 + 2x = 2
What is the solution set for the equations yx-6 and yx plus 2?
What is the solution set for the equations x-y=2 and -x+y=2
What is2 ½ as a fraction?
5/2
How do you get 2 to the 10th power on a TI-30XA calculator?
On my TI-36X, it's 2 yx 1 0 = Thank you.
What number of tiles that will make a rectangle that is2 tiles wide?
The answer is 2*k where k is any integer greater than 0.
Use the Substitution method to solve the system of equationsx plus y equals -4 and x - y equals 2?
x + y = -4x - y = 2x - y = 2x + y - y = 2 + yx = 2 + yx + y = -42 + y + y = -42 + 2y = -42 - 2 + 2y = -4 - 22y = -62y/2 = -6/2y = -3x = 2 + yx = 2 - 3x = -1The solution of the system is (-1, -3)
What is2 cubed?
2 x 2 x 2 = 2 cubed
What is2 in word form?
Two
Is 0 2 a solution to y -x plus 2?
Yes, 0, 2 is a solution to y=-x+2 because 0=-2+2 which can be rewritten as 2-2=0.
What is2?
2 is the second number on the positive side. -2 is 2's opposite.
What is the solution to (0 -4) (0 -2)?
If they are to be multiplied then the solution is 8
Is (02) a solution to y -x 2?
To determine if (0, 2) is a solution to the equation ( y = x^2 ), we substitute ( x = 0 ) into the equation. This gives us ( y = 0^2 = 0 ). Since the corresponding ( y ) value is 0 and not 2, (0, 2) is not a solution to the equation ( y = x^2 ).
