0
What else can I help you with?
What are the solution -2 x -2?
0
Does x plus y equals 4 have one solution no solution or infinite number of solutions?
4+0=4 3+1=4 2+2=4 1+3=4 0+4=4 -1+5=4 -2+6=4 ...
Is (2 0) a solution to y -x 2?
Yes, because if you sub in for x and y, you get 4-0=4 and this is true
What is the solution of the equation x2-2x plus 4 equals 0?
If you mean to say (x^2)-2x+4=0 then there is no solution for x because the equation never makes it to 0 If you mean to say 2x-2x+4=0 then there is no solution for x because it is a horizontal line at Y=4
What is the solution for the ordered pair (04)?
One possible solution is x2 + (y - 4)2 = 0.
What are the solution -2 x -2?
0
What is solution using digits 1 2 4 and 8 to get an answer of 0?
(2*4)-(1*8) = 0
Does x plus y equals 4 have one solution no solution or infinite number of solutions?
4+0=4 3+1=4 2+2=4 1+3=4 0+4=4 -1+5=4 -2+6=4 ...
Is (2 0) a solution to y -x 2?
Yes, because if you sub in for x and y, you get 4-0=4 and this is true
Is 2 0 a solution of 2x - y 4?
Yes, because if you sub in for x and y, you get 4-0=4 and this is true
Is (2 0) a solution of 2x - y 4?
Yes, because if you sub in for x and y, you get 4-0=4 and this is true
What is the solution of the equation x2-2x plus 4 equals 0?
If you mean to say (x^2)-2x+4=0 then there is no solution for x because the equation never makes it to 0 If you mean to say 2x-2x+4=0 then there is no solution for x because it is a horizontal line at Y=4
What is the solution of 28-44 equals 0?
2*8 - 4*4 = 0, otherwise insert "does not" before equals.
What is the solution for the ordered pair (04)?
One possible solution is x2 + (y - 4)2 = 0.
What is the solution set to the inequality 5(x 2)(x 4) 0?
To solve the inequality (5(x - 2)(x - 4) \geq 0), we first find the critical points by setting the expression equal to zero: (x - 2 = 0) and (x - 4 = 0), giving us (x = 2) and (x = 4). The sign of the expression changes at these points. Testing intervals around these points, we find that the solution set is (x \leq 2) or (x \geq 4). Thus, the solution set is ((-\infty, 2] \cup [4, \infty)).
What is the solution to x2-6x plus 8 equals 0?
x2 - 6x + 8 = 0 x2 - 4x - 2x + 8 = 0 x*(x - 4) - 2*(x - 4) = 0 (x - 2)*(x - 4) = 0 so (x - 2) = 0 or (x - 4) = 0 ie x = 2 or x = 4
What is the solution to a equals 3a plus 4?
a = 3a + 4 0 = 2a + 4 2a = -4 a = -2
