0
4+0=4 3+1=4 2+2=4 1+3=4 0+4=4 -1+5=4 -2+6=4 ...
Yes, because if you sub in for x and y, you get 4-0=4 and this is true
If you mean to say (x^2)-2x+4=0 then there is no solution for x because the equation never makes it to 0 If you mean to say 2x-2x+4=0 then there is no solution for x because it is a horizontal line at Y=4
One possible solution is x2 + (y - 4)2 = 0.
0
(2*4)-(1*8) = 0
4+0=4 3+1=4 2+2=4 1+3=4 0+4=4 -1+5=4 -2+6=4 ...
Yes, because if you sub in for x and y, you get 4-0=4 and this is true
Yes, because if you sub in for x and y, you get 4-0=4 and this is true
Yes, because if you sub in for x and y, you get 4-0=4 and this is true
If you mean to say (x^2)-2x+4=0 then there is no solution for x because the equation never makes it to 0 If you mean to say 2x-2x+4=0 then there is no solution for x because it is a horizontal line at Y=4
2*8 - 4*4 = 0, otherwise insert "does not" before equals.
One possible solution is x2 + (y - 4)2 = 0.
x2 - 6x + 8 = 0 x2 - 4x - 2x + 8 = 0 x*(x - 4) - 2*(x - 4) = 0 (x - 2)*(x - 4) = 0 so (x - 2) = 0 or (x - 4) = 0 ie x = 2 or x = 4
a = 3a + 4 0 = 2a + 4 2a = -4 a = -2
Yes. x2-4x+4=0 (x-2)(x-2)=0 x=2