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Yes, 0, 2 is a solution to y=-x+2 because 0=-2+2 which can be rewritten as 2-2=0.
Yes, because if you sub in for x and y, you get 4-0=4 and this is true
y = 0x = y + 2plug 0 in for yx = 0 + 2x = 2
To find the solution set of the equations ( y = x^2 - 2x + 7 ) and ( y = x + 7 ), we can set them equal to each other: ( x^2 - 2x + 7 = x + 7 ). Simplifying this gives ( x^2 - 3x = 0 ), which factors to ( x(x - 3) = 0 ). Thus, the solutions for ( x ) are ( x = 0 ) and ( x = 3 ). Substituting these values back into ( y = x + 7 ) yields the points ( (0, 7) ) and ( (3, 10) ) as the solution set.
Probably yes. But it is difficult to be sure because the browser used for posting question is rubbish and strips out most mathematical symbols. Consequently, we cannot see the equation and have to guess where the equality symbol might be.
Yes, 0, 2 is a solution to y=-x+2 because 0=-2+2 which can be rewritten as 2-2=0.
Yes, because if you sub in for x and y, you get 4-0=4 and this is true
y = 0x = y + 2plug 0 in for yx = 0 + 2x = 2
To find the solution set of the equations ( y = x^2 - 2x + 7 ) and ( y = x + 7 ), we can set them equal to each other: ( x^2 - 2x + 7 = x + 7 ). Simplifying this gives ( x^2 - 3x = 0 ), which factors to ( x(x - 3) = 0 ). Thus, the solutions for ( x ) are ( x = 0 ) and ( x = 3 ). Substituting these values back into ( y = x + 7 ) yields the points ( (0, 7) ) and ( (3, 10) ) as the solution set.
Probably yes. But it is difficult to be sure because the browser used for posting question is rubbish and strips out most mathematical symbols. Consequently, we cannot see the equation and have to guess where the equality symbol might be.
Yes, because if you sub in for x and y, you get 4-0=4 and this is true
Yes, because if you sub in for x and y, you get 4-0=4 and this is true
y = (x + 2)2 andy = (2x)2(x-2)2 + (y-16)2 = 0
Yes if x=2 and y=2, then x=y
Yes.
Without an equality sign the given terms have no solutions.
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